B. Do the followingFind the mean, variance and the standard deviation of the probability distribution of the randomvariable X,:1. which can take only values, 1, 2, and 3, given that P(1) = 1/33, P(2) = 3, and P(3) = 12/33-2. which can take only values, 3, 5, and 7, given that P(3) = 7/30, P(5) = 13, and P(7) = 13/30-3. which can take only values, 2, 4, 5 and 9, given that P(2) = /20 P(4) = 1/20, P(5) =1/5:and P(9) = 3/104. Find the mean, variance and the standard deviation of the probability distribution of the randomvariable X if 1/10 for X = 1, 2, 3, .., 10.%3D%3D%3!%3D%3D%3D%3D

Given that ; X is a random variable. X takes values 1 , 2 , 3 and corresponding probability is…

Answered: Find the mean, variance and the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Suppose a discrete random variable X takes only three values 0, 2 and 3. If P(0)=0.5, P(2)=0.2 and P(3)=D0.3 then P(X>1) is equal to: Select one: a. 0.3 b. 0.2 C. 0.5 d. 0
For what model are the following expressions the cumulative probability distribution for response? What is the meaning of the ; ? Pr(Y, 5 j\x)= Pr(5, S a, \x) = Pr(a + B* + + Bixu + &; < a;\x) = Pr(ɛ, sa;-a- B,xX1 -…-- B;Xx |x)
In which probability distribution would a random variable XX have E(X)=λE(X)=λ?
Find the variance and standard deviation of the probability distribution of a random variable X which can take only the values 3,5, and 7, given that P(3) 30 P(5) =, and P(7) = 20 13 %3D 2.
Find the mean the of the probability distribution of the random variable if P(X) = x-3/15 for X= 7,8 and 9.45
Let X be a random variable with the following probability -6 3 distribution: 1 f(x) 4 1 1 - 2 4 Find the variance of the random variable g(X)= (2X +1).
The life of a semiconductor laser at a constant Power is normally distributeel with mean of 488 hours and a standard devication of 208 haurs what is the Probability that a laser life excceeds 588 hours 2 1iwhat is the Probability that a laser life fails before 418 hours? 1il:what is the life in hours that 95% of the laserrs exceed?
Let xbe a binomial random variable with a variance of 0.48, q 0.6 and n=2. Find E(2x-3) 2.4 -1.4 O None O 1.4
The weights of steers in a herd are distributed normally. The variance is 40,000 and the mean steer weight is 1400lbs. Find the probability that the weight of a randomly selected steer is between 1537lbs and 1679lbs Round your answer to four decimal places.
10 The probability that a Poisson variate x takes a positive value is Find the variance and also the probability that x lies (1 – e-1.5). between 1.5 and 1.5. as Jies - 11lys
Is this a legitimate probability distribution? P(x) = (2x - 1)/15 x = 0, 1, 2, 3, 4
3. Table 1 below shows the probability distribution of hurricanes that have made landfall in the Caribbean. The random variable, X, is the category of the hurricane. Category 1 is the weakest hurricane level while category 5 is the strongest. Table 1 x 1 2 3 4 5 P(X=x) 0.41 0.34 0.13 0.07 * a) Find the value of ‘*’. [1] b) Find the expected category of hurricane to make landfall, E(X). [2] c) What is the probability that a Category 4 or stronger hurricane will make landfall?[1] d) Calculate the variance. [3]

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS

Find the mean, variance and the standard deviation of the probability distribution of the random variable X,: 1. which can take only values, 1, 2, and 3, given that P(1) = 1/33. P(2) = 1/3, and P(3) = 12/33- %3! %3D