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Find the mean for the given sample data. Unless otherwise specified, round your answer to one more decimal place than that used for the observations. A simple random sample of local Tupperware dealers commissions (last month) is listed below. A simple random sample of Tupperware dealers' commissions last month $3,648.93 $4116.87 $2,609.40 $2176.20 $4,025.26 $3,158.70 $2,837.88 $2735.46 $1,933.28 $1,660.52 Find the mean and standard deviation of commissions earned last month, then provide the five number summary. Round your answer to the nearest cent. The mean is 2890.25 deviation is 848.79 The five number summary is: and the standard

Find the mean for the given sample data. Unless otherwise specified, round your answer to one more decimal place than that used for the observations. A simple random sample of local Tupperware dealers commissions (last month) is listed below. A simple random sample of Tupperware dealers' commissions last month $3,648.93 $4116.87 $2,609.40 $2176.20 $4,025.26 $3,158.70 $2,837.88 $2735.46 $1,933.28 $1,660.52 Find the mean and standard deviation of commissions earned last month, then provide the five number summary. Round your answer to the nearest cent. The mean is 2890.25 deviation is 848.79 The five number summary is: and the standard

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Find the mean for the given sample data. Unless otherwise specified, round your answer to one more decimal place than that used for the observations. A simple random sample of local Tupperware dealers commissions (last month) is listed below. A simple random sample of Tupperware dealers' commissions last month $3,648.93 $4116.87 $2,609.40 $2176.20 $4,025.26 $3,158.70 $2,837.88 $2735.46 $1,933.28 $1,660.52 Find the mean and standard deviation of commissions earned last month, then provide the five number summary. Round your answer to the nearest cent. The mean is 2890.25 deviation is 848.79 The five number summary is: min = 1660.52 Median 2786.67 , max = and the standard Q1² 2176.2 4116.87 23- 3648.93 av a 4 123
Transcribed Image Text:Find the mean for the given sample data. Unless otherwise specified, round your answer to one more decimal place than that used for the observations. A simple random sample of local Tupperware dealers commissions (last month) is listed below. A simple random sample of Tupperware dealers' commissions last month $3,648.93 $4116.87 $2,609.40 $2176.20 $4,025.26 $3,158.70 $2,837.88 $2735.46 $1,933.28 $1,660.52 Find the mean and standard deviation of commissions earned last month, then provide the five number summary. Round your answer to the nearest cent. The mean is 2890.25 deviation is 848.79 The five number summary is: min = 1660.52 Median 2786.67 , max = and the standard Q1² 2176.2 4116.87 23- 3648.93 av a 4 123
Expert Solution
Step 1

Answer:- Given random sample,  3648.93,4116.87,2609.40,2176.20,4025.26,3158.70,2837.88,2735.46,1933.28,1660.52 

Now, the sample in ascending order - 

1660.52, 1933.28, 2176.20, 2609.40, 2735.46, 2837.88, 3158.70, 3648.93, 4025.26, 4116.87

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