Find the matrix A of the quadratic form associated with the equation. 10x2 + 10y? + 10z2 + 10xy + 10xz + 10yz - 1 = 0 A Find the equation of the rotated quadratic surface in which the xy-, xz-, and yz-terms have been eliminated. (Use xp, yp, and zp as the new coordinates.)

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### Quadratic Forms in Linear Algebra

**Problem Statement:**

Find the matrix \(A\) of the quadratic form associated with the equation:

\[ 10x^2 + 10y^2 + 10z^2 + 10xy + 10xz + 10yz - 1 = 0 \]

\[\mathbf{A} = \begin{bmatrix}
& & \\
& & \\
& &
\end{bmatrix}\]

Find the equation of the rotated quadratic surface in which the \(xy\)-, \(xz\)-, and \(yz\)-terms have been eliminated. (Use \(xp\), \(yp\), and \(zp\) as the new coordinates.) 

\[\boxed{}\]

**Solution Steps:**

1. **Formulating the Quadratic Form Matrix:**

   The given quadratic equation can be represented in a matrix form \( \mathbf{x}^\top \mathbf{A} \mathbf{x} \), where \( \mathbf{x} = \begin{bmatrix} x \\ y \\ z \end{bmatrix} \).

   To find the matrix \(\mathbf{A}\), we need to identify the coefficients of \(x^2\), \(y^2\), \(z^2\), \(xy\), \(xz\), and \(yz\). For our given equation:

   - The coefficient of \(x^2\) is 10.
   - The coefficient of \(y^2\) is 10.
   - The coefficient of \(z^2\) is 10.
   - The coefficient of \(xy\) is 10 (which means each \(A_{12}\) and \(A_{21}\) is \(\frac{10}{2}\)).
   - The coefficient of \(xz\) is 10 (which means each \(A_{13}\) and \(A_{31}\) is \(\frac{10}{2}\)).
   - The coefficient of \(yz\) is 10 (which means each \(A_{23}\) and \(A_{32}\) is \(\frac{10}{2}\)).

   This leads us to the matrix \( \mathbf{A} \):

   \[
   \mathbf{A} = \begin{bmatrix}
   10 & 5 & 5 \\
   5 & 10 & 5 \\
Transcribed Image Text:### Quadratic Forms in Linear Algebra **Problem Statement:** Find the matrix \(A\) of the quadratic form associated with the equation: \[ 10x^2 + 10y^2 + 10z^2 + 10xy + 10xz + 10yz - 1 = 0 \] \[\mathbf{A} = \begin{bmatrix} & & \\ & & \\ & & \end{bmatrix}\] Find the equation of the rotated quadratic surface in which the \(xy\)-, \(xz\)-, and \(yz\)-terms have been eliminated. (Use \(xp\), \(yp\), and \(zp\) as the new coordinates.) \[\boxed{}\] **Solution Steps:** 1. **Formulating the Quadratic Form Matrix:** The given quadratic equation can be represented in a matrix form \( \mathbf{x}^\top \mathbf{A} \mathbf{x} \), where \( \mathbf{x} = \begin{bmatrix} x \\ y \\ z \end{bmatrix} \). To find the matrix \(\mathbf{A}\), we need to identify the coefficients of \(x^2\), \(y^2\), \(z^2\), \(xy\), \(xz\), and \(yz\). For our given equation: - The coefficient of \(x^2\) is 10. - The coefficient of \(y^2\) is 10. - The coefficient of \(z^2\) is 10. - The coefficient of \(xy\) is 10 (which means each \(A_{12}\) and \(A_{21}\) is \(\frac{10}{2}\)). - The coefficient of \(xz\) is 10 (which means each \(A_{13}\) and \(A_{31}\) is \(\frac{10}{2}\)). - The coefficient of \(yz\) is 10 (which means each \(A_{23}\) and \(A_{32}\) is \(\frac{10}{2}\)). This leads us to the matrix \( \mathbf{A} \): \[ \mathbf{A} = \begin{bmatrix} 10 & 5 & 5 \\ 5 & 10 & 5 \\
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