Find the mass of the lighter body m. Take the plate's mass, the acceleration due to gravity, the mass of the heavier body and the distance of the support from the care (L,g,M,D) to be known.
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Find the mass of the lighter body m. Take the plate's mass, the acceleration due to gravity, the mass of the heavier body and the distance of the support from the care (L,g,M,D) to be known.
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- A uniform ladder of mass (m= 13.5 kg) and length (L) leans against a frictionless wall. If the angle ©60.0°, find the static friction force between the ladder and the floor when a 60.0-kg person stands two-third of the wayup the ladder?Consider a method for measuring the mass of a person’s arm in anatomical studies. The subject lies on her back, extends her relaxed arm to the side and two scales are placed below the arm. One is placed under the elbow and the other under the back of her hand. Construct a problem in which you calculate the mass of the arm and find its center of mass based on the scale readings and the distances of the scales from the shoulder joint. You must include a free body diagram of the arm to direct the analysis. Consider changing the position of the scale under the hand to provide more information, if needed. You may wish to consult references to obtain reasonable mass values.A ladder of length 2L and mass M is positioned on level ground leaning against a wall such that the angle between the ladder and the horizontal is a. The coefficient of static friction between the ladder and the wall and between the ladder and the ground is jistatic = 0.66. The centre of mass ofthe ladder is halfway along it. Draw a diagram indicating all the forces acting on the ladder, and state what each force represents. Also show the direction of the a- and y-axes you will use.
- The figure below shows an arm that is balancing a carton of milk in the hand. The mass of the carton of milk is 1.77 kg, and in the figure is the gravitational force on the carton. The biceps muscle applies a force Fg to the forearm directed up and to the right at an angle of 75.0° from vertical. The point where F is applied to the forearm is 8.00 cm to the left of the elbow joint and 25.0 cm to the right of the center of gravity of the milk carton. (For simplicity, ignore the weight of the forearm.) B Milk N -25.0 cm- What is the magnitude of FB (in N)? 75.0⁰ 8.00 cm iWhen you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a forearm with hand is 1.60 kg. If the biceps is connected to the forearm a distance of 2.4 cm from the elbow, how much force must the biceps exert to hold a 42 N ball at the end of the forearm at distance of 36.0 cm from the elbow, with the forearm parallel to the floor, in Newtons? Use g = 10.0 m/s2. Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.a meter log is a uniform bar of mass m = 77 kg. You want to support it at a rest parallel to the ground. so you place it on a triangle support at 33 cm mark and tie it with a rope on the ground at the 28 cm mark. A) draw your own configuration out. calculate the tension of the rope ____ N, downward, upward, right, left, or none and support force provided by the triangle support _______ N, downward, upward, right, left, or none b) suppose a gumdrop (point mass mb = 14.00 kg) hangs on to the meter log at the 91 cm mark How large will the tension be on the rope? ______ N conceptually explain why it should increase, decrease, or stay the same, compared to part A. C) Now with everything including the gumdrop, the triangle support has been moved away from the rope, to the end of the meter log.Explain why the system itself cannot stay balanced anymore, and the rope goes (T→0). Calculate: rotational inertia of the system below. I = _______ kg·m2Calculate the sizes (+ only) of both the…
- Needs Complete typed solution with 100 % accuracy.A 100-N board 12-m long, rests on two supports, one support is 1m from the end and other is 3 m from the end of the board. A 400-N block is placed on the board 3 m from one end. Find the force exerted by each support on the board.a meter log is a uniform bar of mass m = 77 kg. You want to support it at a rest parallel to the ground. so you place it on a triangle support at 33 cm mark and tie it with a rope on the ground at the 28 cm mark. A) draw your own configuration out. calculate the tension of the rope ____ N, downward, upward, right, left, or none and support force provided by the triangle support _______ N, downward, upward, right, left, or none b) suppose a gumdrop (point mass mb = 14.00 kg) hangs on to the meter log at the 91 cm mark How large will the tension be on the rope? ______ N conceptually explain why it should increase, decrease, or stay the same, compared to part A. C) Now with everything including the gumdrop, the triangle support has been moved away from the rope, to the end of the meter log.Explain why the system itself cannot stay balanced anymore, and the rope goes (T→0). Calculate: rotational inertia of the system below. I = _______ kg·m2Calculate the sizes (+ only) of both the…