Find the margin of error.95% confidence interval; n = 21; 0.37; s = 0.370.1800.1680.1440.151IX-X||=

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Score: 0 of 1 point In a random sample of six mobile devices, the mean repair cost was $65.00 and the standard deviation was $11.50. Assume the population is normally distributed and use a t-distrībution to and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population mean p is ( ). (Round to two decimal places as needed.) The margin of error is $ (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. O A. It can be said that 99% of mobile devices have a repair cost between the bounds of the confidence interval. O B. With 99% confidence, it can be said that the repair cost is between the bounds of the confidence interval. O C. With 99% confidence, it can be said that the population mean repair cost is between the bounds of the confidence interval. O D. If a large sample of mobile devices are taken approximately 99% of them will have repair costs between the bounds of the…
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given. Margin of error, Eequals=6.1 grams; sample standard deviation, sequals=65.6grams The required sample size is _______? (Round up to the nearest whole number.
statistics practitioner took a random sample of 48 observations from a population whose standard deviation is 23 and computed the sample mean to be 100. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 95% confidence, changing the population standard deviation to 47; Confidence Interval = C. Estimate the population mean with 95% confidence, changing the population standard deviation to 10; Confidence Interval =
Find the critical value t, for the confidence level c = 0.99 and sample size n = 12. Click the icon to view the t-distribution table. (Round to the nearest thousandth as needed.) View an example Get more help - Help me solve this
A new fertilizer was applied to the soil of 290 bean plants., 30% showed increased growth. Find the margin of error and 95% confidence interval for the precentage of all bean plants which show increased growth after application of the fertilizer. Round to 2 decimals 1. Margin of Error (as a percentage) 2. Confidence Interval ____________% to _____________%.
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If n = 550 and X = 440, construct a 90% confidence interval for the population proportion, p. Give your answers to three decimals < p <
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error=$7,standard deviation=$22 The required sample size is _____________ (Round up to the nearest whole number as needed.)
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Use the standard normal distribution or the t-distribution to construct a 90% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 46 people, the mean body mass index (BMI) was 27.8 and the standard deviation was 6.09. Which distribution should be used to construct the confidence interval? Choose the correct answer below. ○ A. Use a t-distribution because the sample is random, the population is normal, and σ is unknown. ○ B. Use a normal distribution because the sample is random, the population is normal, and σ is known. ○ C. Use a t-distribution because the sample is random, n ≥30, and σ is unknown. ○ D. Use a normal distribution because the sample is random, n ≥30, and σ is known. ○ E. Neither a normal distribution nor a t-distribution can be used because either the sample is not random, or n <30, and the population is not known to be normal.

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Find the margin of error. 95% confidence interval; n = 21; 0.180 0.168 0.144 0.151 21;= 0.37; s = 0.37 IX