### Finding the Margin of ErrorTo find the margin of error for the given values of \( c \), \( s \), and \( n \):Given:- \( c \) (confidence level) = 0.99- \( s \) (sample standard deviation) = 2.1- \( n \) (sample size) = 17**Step 1:** Click the icon to view the t-distribution table.### t-Distribution TableThe t-distribution table is a statistical table that shows the critical values of the t-distribution. The table is organized as follows:- **Levels of confidence (\( c \))**: 0.80, 0.90, 0.95, 0.98, and 0.99.- **Degrees of freedom (\( \text{d.f.} \))**: The number of values in the final calculation of a statistic that are free to vary.For each combination of confidence level and degrees of freedom, the table provides the t-values to be used in statistical calculations.Example rows include:- For \( \text{d.f.} = 1 \): - \( c = 0.80 \rightarrow \text{t-value} = 3.078 \) - \( c = 0.99 \rightarrow \text{t-value} = 31.821 \)- For \( \text{d.f.} = 17 \): - \( c = 0.80 \rightarrow \text{t-value} = 1.333 \) - \( c = 0.99 \rightarrow \text{t-value} = 2.898 \)**Step 2:** With \( n = 17 \), the degrees of freedom (\( \text{d.f.} \)) are \( n - 1 = 16 \).Looking at the row for \( \text{d.f.} = 16 \) under the column for \( c = 0.99 \):- The t-value is 2.921.**Step 3:** Calculate the margin of error.\[\text{Margin of Error} = t \times \left( \frac{s}{\sqrt{n}} \right)\]Substitute the values:\[\text{Margin of Error} = 2.921 \times \left( \frac

Given,c=0.99 , s=2.1 , n=17degrees of freedom(df)=n-1df=17-1=16α=1-0.99=0.01α2=0.005t0.005(16)=2.921…

Answered: Find the margin of error for the given…

A First Course in Probability (10th Edition)

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Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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