Find the margin of error for the given values of c, s, and n.c = 0.90, s = 4, n = 20Click the icon to view the t-distribution table.The margin of error is. (Round to one decimal place as needed.)t-Distribution Tabled.f.12345678910111213141516171819202122232425Level ofconfidence, cOne tail, aTwo tails, a0.800.100.203.0780.90 0.950.050.0250.10 0.050.980.010.024.5413.7476.314 12.706 31.821 63.6571.8862.920 4.303 6.9651.638 2.353 3.1821.533 2.132 2.7761.476 2.015 2.5711.440 1.943 2.4471.415 1.895 2.3651.397 1.860 2.306 2.8963.3653.1432.9989.9255.8414.6044.0323.7073.4993.3551.383 1.833 2.262 2.821 3.2501.372 1.812 2.228 2.764 3.169 101.363 1.796 2.201 2.718 3.106 111.356 1.782 2.179 2.681 3.055 121.350 1.771 2.160 2.650 3.012 131.345 1.761 2.145 2.624 2.977 141.341 1.753 2.131 2.602 2.947 151.337 1.746 2.120 2.583 2.921 161.333 1.740 2.110 2.567 2.898 171.330 1.734 2.101 2.552 2.878 181.328 1.729 2.093 2.539 2.861 191.325 1.725 2.086 2.528 2.845 201.323 1.721 2.080 2.518 2.831 211.321 1.717 2.074 2.508 2.819221.319 1.714 2.069 2.500 2.8071.318 1.711 2.064 2.492 2.7971.316 1.708 2.060 2.485 2.7872324250.990.0050.01 d.f.23456700 gIX

Given,c=0.90 , s=4 , n=20derees of freedom(df)=n-1df=20-1=19α=1-0.90=0.1α2=0.05t0.05(19)=1.729…

Answered: Find the margin of error for the given…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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t-Distribution Table d.f. 123456789 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 Level of confidence, c 0.80 0.90 0.95 0.98 0.10 0.05 0.025 0.01 0.10 0.05 0.02 0.20 3.078 6.314 12.706 31.821 1.886 2.920 4.303 6.965 1.638 2.353 3.182 4.541 1.533 2.132 2.776 3.747 1.476 2.015 2.571 3.365 1.440 1.943 2.447 3.143 1.415 1.895 2.365 2.998 1.397 1.860 2.306 2.896 1.383 1.833 2.262 2.821 1.372 1.812 2.228 2.764 2.201 2.718 2.179 2.681 3.055 2.160 2.650 3.012 2.624 2.977 2.131 2.602 2.947 2.583 2.921 2.898 2.567 2.552 2.878 One tail, a Two tails, a 0.99 0.005 0.01 d.f. 63.657 1 9.925 2 5.841 3 4.604 4 4.032 5 3.707 6 3.499 7 3.355 8 3.250 9 3.169 10 3.106 11 12 13 14 15 16 17 18 2.539 2.861 19 1.363 1.796 1.356 1.782 1.350 1.771 1.345 1.761 2.145 1.341 1.753 1.337 1.746 2.120 1.333 1.740 2.110 1.330 1.734 2.101 1.328 1.729 2.093 2.086 2.528 1.325 1.725 2.845 20 1.323 1.721 2.080 2.518 2.831 21 1.321 1.717 2.074 2.508 2.819 22 1.319 1.714 2.069 2.500…
Find the margin of error for the given values of c, s, and n. c= 0.99, s= 2.7, n = 12 Click the icon to view the t-distribution table. The margin of error is . (Round to one decimal place as needed.)
Find the margin of error for the given values of c, s, and n. c= 0.90, s = 3.7, n= 22 Click the icon to view the t-distribution table. The margin of error is (Round to one decimal place as needed.)
The accompanying data represent the wait time (in minutes) for a random sample of 40 visitors to a popular attraction in a large amusement park. Use the sample data to complete parts (a) through (d). Click the icon to view the data for wait times. (a) Construct a relative frequency histogram of the data. Comment on the shape of the distribution. Choose the correct graph below. O A. ARelative Freq. 0.6- 0+ 60 Wait Time (min.) What is the shape of the distribution? O O E A. Q 60 B. No A. Yes, there is(are) B. A Relative Freq. 0.6 outlier(s). 07 0 60 Wait Time (min.) O A. The distribution is bell-shaped and roughly symmetric about its peak between 25 and 30 minutes. B. The distribution is right-skewed because the peak is between 0 and 5 minutes and the right tail is much longer than the left tail. C. The distribution is left-skewed because the peak is between 55 and 60 minutes and the left tail is much longer than the right tail. D. The distribution is right-skewed because the peak is…
Q4
The gas mileages (in miles per gallon) for 38 cars are shown in the frequency distribution. Approximate the mean of the frequency distribution. The approximate mean of the frequency distribution is (Round to one decimal place as needed.) Gas Mileage (in miles per gallon) 26-30 31-35 36-40 41-45 Frequency 13 14 4 7 0
Use the Histogram tool to develop a frequency distribution and histogram for the number of months as a customer of the bank in the data below. Compute the relative and cumulative relative frequencies and use a line chart to construct an ogive. Complete the frequency distribution for the months as a customer, and compute the relative and cumulative relative frequencies. (Type integers or decimals rounded to three decimal places as needed.) Bins Frequency Relative Frequency Cumulative Relative Frequency 10 enter your response here enter your response here enter your response here 20 enter your response here enter your response here enter your response here 30 enter your response here enter your response here enter your response here 40 enter your response here enter your response here enter your response here 50 enter your response here enter your response here enter your…
In the US, 46.2% of all people have type O blood, 39.1% have type A blood, 10.4% have type B blood and 4.3% have type AB blood. A researcher wants to see if the distribution of blood type is different for millionaires. The table below shows the results of a random sample of 3116 millionaires. What can be concluded at the a = 0.01 significance level? a. Complete the table by filling in the expected frequencies. Round to the nearest whole number: Frequencies of Blood Type Outcome Frequency Expected Frequency 1434 A 1224 В 310 AB 148 b. What is the correct statistical test to use? Select an answer V c. What are the null and alternative hypotheses? Но: O Blood type and income are independent. O The distribution of blood type for millionaires is not the same as it is for Americans in general. O The distribution of blood type for millionaires is the same as it is for Americans in general. O Blood type and income are dependent.
Make a frequency distribution for the data. X f 1 2 2 20 3 21 4 15 The sample mean is x = (Round to one decimal place as needed.)
1:15 (a) Which variable is the explanatory variable? OA. One of the biggest factors in determining the value of a home is the square footage. The accompanying data represent the square footage and selling price (in thousands of dollars) for a random sample of homes for sale in a certain region. Complete parts (a) through (h) below. Click the icon to view the housing data. Square Footage Selling Price (b) Draw a scatter diagram of the data. Choose the correct scatter diagram below. Ay 4500- 000 1000 mylab.pearson.com/ + ® : 3 4500 Data Table Q Square Footage, x 2148 3231 1177 1988 3064 2735 4146 2215 2625 1629 1773 3887 Print ||| OB. r= 0.899 (Round to three decimal places as needed.) = AX 4500- 1000+++ 150 750 Q (c) Determine the linear correlation coefficient between square footage and asking price. Done Ay 750- Vo) 1 LTE2 150- O 1000 Selling Price ($000s), y D 371.1 382.2 197.6 339.9 614.9 364.7 632.7 377.7 427.5 285.9 268.9 701.4 4500 .... .... Q X D. Ay 750- 41% 150+ 1000 4500
Find the margin of error for the given values of c, s, and n. c=0.99, s=2.1, n=7 The margin of error is [ ] (Round to one decimal place as needed.)
Find the margin of error for the given values of c, s, and n. c = 0.99, s = 3.1, n = 27 Click the icon to view the t-distribution table. The margin of error is (Round to one decimal place as needed.)

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