Find the magnitude and direction of the magnetic field at point A. Tips on next page. Keep/truncate to 4 sig figs on each step. X= 1.0cm I=2.0A × 1=2.0A 1=2.0A

A wire of charge Q1 is bended into the shape of a semicircular wire of radius R, and located in a two dimensional xy-coordinate system as shown in the figure. A point charge of Q2 is located at (0, R/4.3) in this coordinate system. What is Q2/Q1 if the electric potential at point O is zero? Provide your answer with two decimal place. Q1 R

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y P. 2R R. The center of the charged circle of radius R = 50cm in the x-z plane is coincident with the origin of the coordinate system in the figure. The total charge Q on the circle is not uniform, but is distributed according to the relation 1 = v50. Where 0 is the angle between the radius R of the circle and the +x-axis in radian. Find the magnitude of the Electric field due to these charges in the y-axis direction only, at the point P at a distance of 2R. ke 1 Eo = 9x10-12 () and n = 3 4περ Nm² 10 13 a) 15 1013 b) 10 13 1013 d) 105 ) e) 1013 45 75 135

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sec. 4-2 Position and Displacement •1 The position vector for an electron is 7 (5.0 m)i – (3.0 m)j + (2.0 m)k. (a) Find the magnitude of r. (b) Sketch the vector on a right-handed coordinate system.

Problem#3: Magnetism Consider a rectangular loop with dimensions 20.00cm x 35.00cm is placed in a region with uniform magnetic field B = 1.2 T î. The loop is hinged along side ab and carries a clockwise 5.00 A current as shown in the figure. Note: Express all your answers in unit vectors. a.) Find magnitude and direction of the magnetic force in Newton on the rectangular loop. b.) Find the magnetic moment. c.) Find the net torque experience by the rectangular loop.

Find the magnetic field at point P for the following steady current configuration. a

Choose the right Free Body Diagram representation for the Ring shown Select one: A H = 0.15 Hk = 0.12 20° 6" В Hy = 0.15 ek =0.12 20° C 6" H = 0.15 Wk = 0.12 20° 6" Hs = 0.15 Hk= 0.12 20°

Find the area of the circle r = 2(sine + cos0) by means of double integration.