Find the magnitude and direction of the force on charge q3
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A: Electric force on the -10 nC charge F→net=F→1+F→2=kqq1r12-i^+kqq2r22j^=kqq1r12-i^+q2r22j^
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A: Charges are given,
Find the magnitude and direction of the force on charge q3
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- A 6.6-μC charge is placed at the origin and a second charge is placed on the x-axis at x = 0.1 m. If the resulting force on the second charge is 5.7 N in the positive x-direction, what is the value of its charge? a. 1.0 μC b. 1.0 nC c. –1.0 μC d. –1.0 nC e. 0 μCWhat is the strength of the electric field 3.0 cm from a small glass bead that has been charged to + 4.0 nC ? Express your answer in newtons per coulombTwo point charges are placed on the x-axis as follows: Charge q1=+4.00nC is located 0.20m,and charge q2=+5.00nC is at x=-0.30m. a.Draw a sketch of te setting discussed in the question above. Make sure to label all points discussed. b. What are the magnitude and direction of the total force exerted by these two charges on a negative point charge q3=-6.00nC that is placed at the origin?
- If two equal charges are separated by a certain distance, the force of repulsion is F. Given F1, if each charge in F1 is doubled and the distance is cut in half, what is the new value of the force of repulsion, F2? Express your answer in terms of F1.Referring to (Figure 1), suppose q2 is not known. Instead, it is given that q1+ q2 = -1.8 μC. Assume that the number of field lines shown precisely represents the ratio of the magnitudes of the charges. Find q1, q2, q3.What s the magnitude and direction of the electric field at .25m from a -5.6 x10^-6 C point charge?