Find the magnetic field inside a solenoid coil with length of 0.02 m with a current of 47 A that has 1592 turns. μ = 1.257 x 10-6 Tm/A = 4 x 10-7 Tm/A

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Chapter1: Units, Trigonometry. And Vectors
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A 626 turn solenoid coil with length of 0.04 m produces a magnetic field of 0.7 T.
How much current in the coil is necessary? μ = 1.257 x 10-6 Tm/A
Transcribed Image Text:A 626 turn solenoid coil with length of 0.04 m produces a magnetic field of 0.7 T. How much current in the coil is necessary? μ = 1.257 x 10-6 Tm/A
Find the magnetic field inside a solenoid coil with length of 0.02 m with a current of
47 A that has 1592 turns.
μ = 1.257 x 10-6 Tm/A = 4 x 10-7 Tm/A
Transcribed Image Text:Find the magnetic field inside a solenoid coil with length of 0.02 m with a current of 47 A that has 1592 turns. μ = 1.257 x 10-6 Tm/A = 4 x 10-7 Tm/A
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