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Find the Maclaurin Expansion to the 4th order of sin(log(1+x)) Sinaz xan? log(1+x) = x - 2² } sin (dog (1+x2) Put the expansion of log in sin (2-2²)-(x - 2)²³ 3! *-2²-2² +0 (x²) the correct solution indicates that there should be a +, please explain why using the maclaurin expansion and not the derivation method

Find the Maclaurin Expansion to the 4th order of sin(log(1+x)) Sinaz xan? log(1+x) = x - 2² } sin (dog (1+x2) Put the expansion of log in sin (2-2²)-(x - 2)²³ 3! *-2²-2² +0 (x²) the correct solution indicates that there should be a +, please explain why using the maclaurin expansion and not the derivation method

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I attached the question and in red I indicated my concern please expalin to me why it should be a + and not a -
Find the Maclaurin Expansion to the 4th order of sin(log(1 +72)) Sinaz xan? 31 log(1+x) = x - 2² } sin (dog[(1+2)) Put the expansion of log in sin (-)) 3! 2-2²-2² +0 (x4) the correct solution indicates the that there should be a +, please explain why using maclaurin expansion and not the derivation method
Transcribed Image Text:Find the Maclaurin Expansion to the 4th order of sin(log(1 +72)) Sinaz xan? 31 log(1+x) = x - 2² } sin (dog[(1+2)) Put the expansion of log in sin (-)) 3! 2-2²-2² +0 (x4) the correct solution indicates the that there should be a +, please explain why using maclaurin expansion and not the derivation method
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