Find the local extrama of f(x)=x²-8x+12 on a closed interval [-2,5] O a. minimum value at x =4 is -4 maximum value at x = - ? is 32 Ob.minimum value at x =5 is -3 maximum value at x =-2 is 32 maximum value at x=-2 is -3 Oc. minimum value at x=4 is 32 d. minimum value at x =4 is -4 maximum value at x =5 is -3

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 97E
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A Ims.cisjubail.gov.sa/webapps/assessment/take/take.jsp?course_assessment id- 67562 18c
maining Time: 1 hour, 04 minutes, 01 second.
mestion Completion Status:
3
4
9
10 110 12D
estion 20
Find the local extrama of f(x)=x²-8x+12 on a closed interval [-2,5]
O a. minimum value at x =4 is -4
maximum value at x =- ? is 32
Ob.minimum value at x =5 is -3
maximum value at x=-2 is 32
Oc. maximum value at x=-2 is -3
minimum value at x =4 is 32
Od. minimum value at x =4 is -4
maximum value at x =5 is -3
AClick Submit to complete this assessment.
ENG
F7
F6
F5
F4
F3 0+
F2 0-
%
Transcribed Image Text:SAMSUNE A Ims.cisjubail.gov.sa/webapps/assessment/take/take.jsp?course_assessment id- 67562 18c maining Time: 1 hour, 04 minutes, 01 second. mestion Completion Status: 3 4 9 10 110 12D estion 20 Find the local extrama of f(x)=x²-8x+12 on a closed interval [-2,5] O a. minimum value at x =4 is -4 maximum value at x =- ? is 32 Ob.minimum value at x =5 is -3 maximum value at x=-2 is 32 Oc. maximum value at x=-2 is -3 minimum value at x =4 is 32 Od. minimum value at x =4 is -4 maximum value at x =5 is -3 AClick Submit to complete this assessment. ENG F7 F6 F5 F4 F3 0+ F2 0- %
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