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Find the linearization of at x = π/6. f(x) = 4 sin x - 3x 1. L(x) 2. L(x) = 2 − 1/2 + (2√3 − 3)(x + 1) = 2 − 1/π + (2√3 − 3)(x − 7) 3. 1 L(x) = 2 + ½3ñ − (2√3+3)(x + 7) 4. 1 L(x) = 2 + ½ñ+ (2√3+3) (x + Z) 5. L(x) = 2 + − (2√3 − 3)(x − 7) 6. L(x) = 2 - 1/2₁ - (2√3+3)(x −75) ホー

Find the linearization of at x = π/6. f(x) = 4 sin x - 3x 1. L(x) 2. L(x) = 2 − 1/2 + (2√3 − 3)(x + 1) = 2 − 1/π + (2√3 − 3)(x − 7) 3. 1 L(x) = 2 + ½3ñ − (2√3+3)(x + 7) 4. 1 L(x) = 2 + ½ñ+ (2√3+3) (x + Z) 5. L(x) = 2 + − (2√3 − 3)(x − 7) 6. L(x) = 2 - 1/2₁ - (2√3+3)(x −75) ホー

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the linearization of at x = π/6. f(x) = 4 sinx - 3x 1*12*132*1 1 * 1. L(x) 2. L(x) = 2 − 1/π + (2√3 − 3)(x − 2) - 3. 1 |L(x) = 2 + ½3ñ− (2√3+3)(x + 7) 5. = 2 − 1 2π + (2√3 − 3)(x + 1) - 4. 1 L(x) = 2 + ½ñ+ (2√3+3) (x + 7) L(x) = 2 + = π − (2√3 − 3)(x − 7) 6. L(x) = 2 - 1/2₁ 1 5 * 1 6 * 17 * 10 * 1 T- − 0* (2√3+3)(x - 5) 10* X LL T I 12
Transcribed Image Text:Find the linearization of at x = π/6. f(x) = 4 sinx - 3x 1*12*132*1 1 * 1. L(x) 2. L(x) = 2 − 1/π + (2√3 − 3)(x − 2) - 3. 1 |L(x) = 2 + ½3ñ− (2√3+3)(x + 7) 5. = 2 − 1 2π + (2√3 − 3)(x + 1) - 4. 1 L(x) = 2 + ½ñ+ (2√3+3) (x + 7) L(x) = 2 + = π − (2√3 − 3)(x − 7) 6. L(x) = 2 - 1/2₁ 1 5 * 1 6 * 17 * 10 * 1 T- − 0* (2√3+3)(x - 5) 10* X LL T I 12
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