Find the linearization L(x) of f(x) at x = a. f(x) a = 0 %3D 7x +4 L(x) 16 ** 16 L(x) 16 4. 7 L(x) = - 7 L(x) = 16 16 14

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Find the Linearization \( L(x) \) of \( f(x) \) at \( x = a \).**

Given:

\[ f(x) = \frac{1}{7x + 4}, \quad a = 0 \]

**Options for \( L(x) \):**

1. \( L(x) = -\frac{7}{16}x + \frac{1}{16} \)

2. \( L(x) = \frac{7}{16}x + \frac{1}{4} \)

3. \( L(x) = -\frac{7}{16}x + \frac{1}{4} \)

4. \( L(x) = \frac{7}{16}x + \frac{1}{16} \)

**Instructions:**

Choose the correct linearization expression for \( L(x) \) from the options above. This involves calculating the linear approximation of \( f(x) \) around the point \( a = 0 \).
Transcribed Image Text:**Find the Linearization \( L(x) \) of \( f(x) \) at \( x = a \).** Given: \[ f(x) = \frac{1}{7x + 4}, \quad a = 0 \] **Options for \( L(x) \):** 1. \( L(x) = -\frac{7}{16}x + \frac{1}{16} \) 2. \( L(x) = \frac{7}{16}x + \frac{1}{4} \) 3. \( L(x) = -\frac{7}{16}x + \frac{1}{4} \) 4. \( L(x) = \frac{7}{16}x + \frac{1}{16} \) **Instructions:** Choose the correct linearization expression for \( L(x) \) from the options above. This involves calculating the linear approximation of \( f(x) \) around the point \( a = 0 \).
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