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Find the line that best fit for the data obtained in the study of the number of absences and the final grade of the seven students in the statistics class. Final grade y (%) Number of Student absences x xy A 6. 82 492 36 6,724 7,396 1,849 5,476 2 86 A 4 15 43 645 225 74 666 81 E 12 58 696 450 144 90 8,100 6,084 F 5 25 8. 78 624 64 Ex = 57 Ey = 511 Exy = C Ex? = 579 Ey? = : (Ey)(Ex?) – (Ex)(Exy) n(Ex?) – (Ex)? Σεν) -(Σ) (Σν) n(Ex?) – (Ex)² y' = a + bx

Find the line that best fit for the data obtained in the study of the number of absences and the final grade of the seven students in the statistics class. Final grade y (%) Number of Student absences x xy A 6. 82 492 36 6,724 7,396 1,849 5,476 2 86 A 4 15 43 645 225 74 666 81 E 12 58 696 450 144 90 8,100 6,084 F 5 25 8. 78 624 64 Ex = 57 Ey = 511 Exy = C Ex? = 579 Ey? = : (Ey)(Ex?) – (Ex)(Exy) n(Ex?) – (Ex)? Σεν) -(Σ) (Σν) n(Ex?) – (Ex)² y' = a + bx

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Find the line that best fit for the data obtained in the study of the number of absences and the final grade of the seven students in the statistics class. Final grade y (%) Number of Student absences x ху y? 6,724 7,396 1,849 5,476 В A 6. 82 492 A 36 B 86 4 15 43 645 225 D 74 666 81 E 12 58 696 144 450 8,100 6,084 F 5 90 25 8 78 624 64 Ex = 57 Ey = = 511 Exy = Ex? = 579 Ey = : (Ey)(Ex²) – (Ex)(Exy) n(Ex?) – (Ex)² a = Σχν)-(Σx) (Σν) . n(Ex?) – (Ex)² b = a + bx A В D a b : 172 :: 3,745 : 3,364 : 38,993 :: 39,883 :: 465 :: 102.493 : -3.622 :: -6.332
Transcribed Image Text:Find the line that best fit for the data obtained in the study of the number of absences and the final grade of the seven students in the statistics class. Final grade y (%) Number of Student absences x ху y? 6,724 7,396 1,849 5,476 В A 6. 82 492 A 36 B 86 4 15 43 645 225 D 74 666 81 E 12 58 696 144 450 8,100 6,084 F 5 90 25 8 78 624 64 Ex = 57 Ey = = 511 Exy = Ex? = 579 Ey = : (Ey)(Ex²) – (Ex)(Exy) n(Ex?) – (Ex)² a = Σχν)-(Σx) (Σν) . n(Ex?) – (Ex)² b = a + bx A В D a b : 172 :: 3,745 : 3,364 : 38,993 :: 39,883 :: 465 :: 102.493 : -3.622 :: -6.332
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