Find the limit or indicate that it does not exist. 3 HET [ ( = = 1 ₁ + (000 + ) ₁ + [Tam ² ₁] ] lim sin COS tan k t-xL

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The image presents a mathematical problem involving limits in vector calculus. It asks to find the limit or indicate if it does not exist for the given vector function as \( t \) approaches \( \pi \).

The function is represented as a vector:

\[
\lim_{{t \to \pi}} \left[ \left( \sin \frac{4}{3}t \right) \mathbf{i} + \left( \cos \frac{t}{6} \right) \mathbf{j} + \left( \tan \frac{3}{4}t \right) \mathbf{k} \right]
\]

This is a three-dimensional vector with components:
- For the \( \mathbf{i} \)-component: \(\sin\left(\frac{4}{3}t\right)\)
- For the \( \mathbf{j} \)-component: \(\cos\left(\frac{t}{6}\right)\)
- For the \( \mathbf{k} \)-component: \(\tan\left(\frac{3}{4}t\right)\)

The task is to determine each component's limit as \( t \) approaches \( \pi \) and evaluate if the overall vector limit exists.
Transcribed Image Text:The image presents a mathematical problem involving limits in vector calculus. It asks to find the limit or indicate if it does not exist for the given vector function as \( t \) approaches \( \pi \). The function is represented as a vector: \[ \lim_{{t \to \pi}} \left[ \left( \sin \frac{4}{3}t \right) \mathbf{i} + \left( \cos \frac{t}{6} \right) \mathbf{j} + \left( \tan \frac{3}{4}t \right) \mathbf{k} \right] \] This is a three-dimensional vector with components: - For the \( \mathbf{i} \)-component: \(\sin\left(\frac{4}{3}t\right)\) - For the \( \mathbf{j} \)-component: \(\cos\left(\frac{t}{6}\right)\) - For the \( \mathbf{k} \)-component: \(\tan\left(\frac{3}{4}t\right)\) The task is to determine each component's limit as \( t \) approaches \( \pi \) and evaluate if the overall vector limit exists.
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