Find the limit of the sequence as n approaches infinity: In 1 an 2n + 2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem Statement:**

Find the limit of the sequence as \( n \) approaches infinity:

\[
a_n = \frac{1n - 1}{2n + 2}
\]

---

**Detailed Explanation:**

The sequence given is:

\[
a_n = \frac{n - 1}{2n + 2}
\]

To find the limit as \( n \) approaches infinity, simplify the expression:

1. Divide both the numerator and the denominator by \( n \):

\[
a_n = \frac{\frac{n}{n} - \frac{1}{n}}{\frac{2n}{n} + \frac{2}{n}} = \frac{1 - \frac{1}{n}}{2 + \frac{2}{n}}
\]

2. As \( n \) approaches infinity, the terms \(\frac{1}{n}\) and \(\frac{2}{n}\) approach zero. This simplifies the expression to:

\[
a_n = \frac{1 - 0}{2 + 0} = \frac{1}{2}
\]

**Conclusion:**

The limit of the sequence as \( n \) approaches infinity is \(\frac{1}{2}\).
Transcribed Image Text:**Problem Statement:** Find the limit of the sequence as \( n \) approaches infinity: \[ a_n = \frac{1n - 1}{2n + 2} \] --- **Detailed Explanation:** The sequence given is: \[ a_n = \frac{n - 1}{2n + 2} \] To find the limit as \( n \) approaches infinity, simplify the expression: 1. Divide both the numerator and the denominator by \( n \): \[ a_n = \frac{\frac{n}{n} - \frac{1}{n}}{\frac{2n}{n} + \frac{2}{n}} = \frac{1 - \frac{1}{n}}{2 + \frac{2}{n}} \] 2. As \( n \) approaches infinity, the terms \(\frac{1}{n}\) and \(\frac{2}{n}\) approach zero. This simplifies the expression to: \[ a_n = \frac{1 - 0}{2 + 0} = \frac{1}{2} \] **Conclusion:** The limit of the sequence as \( n \) approaches infinity is \(\frac{1}{2}\).
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