Find the limit a) lim ---3-9 X+ 3 b) lim (6x² - 6 co₁ x) X->0 X->>0 (d) lim X->0 5 COS X coc 5+ sin x 6 4+ e* 2 ? ?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Can you please solve a, b, c and d
Find the limit
(1
a) lim
X + 3
x-3x²9
Ex
b) lim (6x² - 6 cos x) =
X->0
c) lim
X->>0
d) lim
X->0
5 COS X
5+ sin x
6
4+ex
?
?
Transcribed Image Text:Find the limit (1 a) lim X + 3 x-3x²9 Ex b) lim (6x² - 6 cos x) = X->0 c) lim X->>0 d) lim X->0 5 COS X 5+ sin x 6 4+ex ? ?
Expert Solution
Step 1: Introduction

Given:

a) limit as x rightwards arrow negative 3 of fraction numerator x plus 3 over denominator x squared minus 9 end fraction

b) limit as x rightwards arrow 0 of open parentheses 6 x squared minus 6 cos open parentheses x close parentheses close parentheses

c) limit as x rightwards arrow 0 of open parentheses fraction numerator 5 cos open parentheses x close parentheses over denominator 5 plus sin open parentheses x close parentheses end fraction close parentheses

d) limit as x rightwards arrow 0 of fraction numerator 6 over denominator 4 plus e to the power of x end fraction

To Find:

The value of the limits.

Concept Used:

The function has a limit L at an input p, if f open parentheses x close parentheses gets closer and closer to L as x moves closer and closer to p.

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