Find the length x. 4 7 2.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Statement:**

Find the length \( x \).

**Diagram Explanation:**

The image displays a right triangle with one side extended, forming a larger right triangle. 

- The smaller right triangle has a base of 4 units and an adjacent side of 2 units, forming a right angle.
- The larger triangle shares a hypotenuse with the smaller triangle labeled as 7 units.
- The hypotenuse of the larger triangle is labeled \( x \).

To find \( x \), apply the Pythagorean theorem for the larger triangle: 

\( 4 + 2 = 6 \). 

Use:

\[ \text{Hypotenuse}^2 = \text{Longer side}^2 + 7^2 \]

Thus:

\[ x = \sqrt{6^2 + 7^2} \]

Calculate:

\[ x = \sqrt{36 + 49} \]
\[ x = \sqrt{85} \]

Therefore, \( x = \sqrt{85} \approx 9.22 \) units.
Transcribed Image Text:**Problem Statement:** Find the length \( x \). **Diagram Explanation:** The image displays a right triangle with one side extended, forming a larger right triangle. - The smaller right triangle has a base of 4 units and an adjacent side of 2 units, forming a right angle. - The larger triangle shares a hypotenuse with the smaller triangle labeled as 7 units. - The hypotenuse of the larger triangle is labeled \( x \). To find \( x \), apply the Pythagorean theorem for the larger triangle: \( 4 + 2 = 6 \). Use: \[ \text{Hypotenuse}^2 = \text{Longer side}^2 + 7^2 \] Thus: \[ x = \sqrt{6^2 + 7^2} \] Calculate: \[ x = \sqrt{36 + 49} \] \[ x = \sqrt{85} \] Therefore, \( x = \sqrt{85} \approx 9.22 \) units.
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