Find the inverse z-transform of 1 = (2)X (1– az¯1)? |z|>|a| |

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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**Problem Statement:**

Find the inverse z-transform of 

\[ X(z) = \frac{1}{(1 - az^{-1})^2} \]

for \(|z| > |a|\).

**Solution Approach:**

To find the inverse z-transform of the given expression, we can utilize properties or known inverse z-transforms and convolution theorems. The inverse z-transform of \(\frac{1}{(1 - az^{-1})}\) is known, and then convolution techniques can be applied due to the power of the denominator. As a result, the convolution yields the required time-domain signal.

**Key Points:**

- The region of convergence \(|z| > |a|\) implies a causal sequence.
- Since the expression involves a power, repeated transformations or convolutions must be done.
Transcribed Image Text:**Problem Statement:** Find the inverse z-transform of \[ X(z) = \frac{1}{(1 - az^{-1})^2} \] for \(|z| > |a|\). **Solution Approach:** To find the inverse z-transform of the given expression, we can utilize properties or known inverse z-transforms and convolution theorems. The inverse z-transform of \(\frac{1}{(1 - az^{-1})}\) is known, and then convolution techniques can be applied due to the power of the denominator. As a result, the convolution yields the required time-domain signal. **Key Points:** - The region of convergence \(|z| > |a|\) implies a causal sequence. - Since the expression involves a power, repeated transformations or convolutions must be done.
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