Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 0.65 The indicated IQ score, x, is (Round to one decimal place as needed.)
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 0.65 The indicated IQ score, x, is (Round to one decimal place as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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10,11- Hi, I need help with these 2 short exercises from stats. Please help and thanks in advance.
- [Click to view page 2 of the table.](#)
**Graph Explanation:**
The graph is a normal distribution curve representing IQ scores. Key features of the graph:
- The curve is symmetrical, centering around the mean of 100.
- The shaded area under the curve represents a proportion of the population.
- For this problem, the shaded area accounts for 0.65 of the distribution, indicating that 65% of the population has an IQ score less than the value \(x\).
**Task:**
Given the graph and the distribution, determine the indicated IQ score \(x\).
**Instructions:**
Ensure to round your final answer to one decimal place as needed.
**Solution Framework:**
1. Utilize standard normal distribution (Z-table) resources through the provided links.
2. Calculate \(x\) using the transformation formula:
\[ x = \mu + z\sigma \]
where \(\mu\) is the mean, \(z\) is the Z-score corresponding to a cumulative probability of 0.65, and \(\sigma\) is the standard deviation.
**Answer:**
The indicated IQ score, \(x\), is [Input Field]. (Round to one decimal place as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22c22731-3858-419d-b4a1-f1d81ff5f2b6%2F66db81f2-eaaa-43d7-a542-aef198824481%2Fa9e3ehq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Educational Content on IQ Scores
**Problem Statement:**
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.
**Resources Available:**
- [Click to view page 1 of the table.](#)
- [Click to view page 2 of the table.](#)
**Graph Explanation:**
The graph is a normal distribution curve representing IQ scores. Key features of the graph:
- The curve is symmetrical, centering around the mean of 100.
- The shaded area under the curve represents a proportion of the population.
- For this problem, the shaded area accounts for 0.65 of the distribution, indicating that 65% of the population has an IQ score less than the value \(x\).
**Task:**
Given the graph and the distribution, determine the indicated IQ score \(x\).
**Instructions:**
Ensure to round your final answer to one decimal place as needed.
**Solution Framework:**
1. Utilize standard normal distribution (Z-table) resources through the provided links.
2. Calculate \(x\) using the transformation formula:
\[ x = \mu + z\sigma \]
where \(\mu\) is the mean, \(z\) is the Z-score corresponding to a cumulative probability of 0.65, and \(\sigma\) is the standard deviation.
**Answer:**
The indicated IQ score, \(x\), is [Input Field]. (Round to one decimal place as needed.)
![In a certain study, the chance of encountering a car crash on the road is stated as 25%. Express the indicated degree of likelihood as a probability value between 0 and 1 inclusive.
The probability is [ ]. (Round to two decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22c22731-3858-419d-b4a1-f1d81ff5f2b6%2F66db81f2-eaaa-43d7-a542-aef198824481%2Frg0bh0f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In a certain study, the chance of encountering a car crash on the road is stated as 25%. Express the indicated degree of likelihood as a probability value between 0 and 1 inclusive.
The probability is [ ]. (Round to two decimal places as needed.)
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