Find the indicated derivative. df If f(x) = x3, find dx 8 df dx |x = -11 || X 32 X = 10 X 1 2 11

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Find the indicated derivative.**

Given \( f(x) = x^3 \), we need to find \(\left. \frac{df}{dx} \right|_{x = -11} \).

The attempted solution provided in the image is:

\[
\left. \frac{df}{dx} \right|_{x = -11} = \frac{-8}{x^{\frac{3}{2}}} + \frac{10}{x^{\frac{1}{2}}}
\]

However, this solution is incorrect, as indicated by the red "X" symbol next to it. 

**Explanation of the Provided Solution Steps:**
- The provided solution attempts to evaluate the derivative by showing fractional exponents in terms of \( x \).
- The terms \(\frac{-8}{x^{3/2}}\) and \(\frac{10}{x^{1/2}}\) do not relate correctly to the derivative of the function \( f(x) = x^3 \).

Let's correctly solve the problem:

1. **Find the derivative of \( f(x) \):**
   \[
   f(x) = x^3
   \]
   \[
   \frac{df}{dx} = 3x^2
   \]

2. **Evaluate the derivative at \( x = -11 \):**
   \[
   \left. \frac{df}{dx} \right|_{x = -11} = 3(-11)^2 = 3 \cdot 121 = 363
   \]

So, the correct value of the derivative at \( x = -11 \) is \(\boxed{363}\).
Transcribed Image Text:**Find the indicated derivative.** Given \( f(x) = x^3 \), we need to find \(\left. \frac{df}{dx} \right|_{x = -11} \). The attempted solution provided in the image is: \[ \left. \frac{df}{dx} \right|_{x = -11} = \frac{-8}{x^{\frac{3}{2}}} + \frac{10}{x^{\frac{1}{2}}} \] However, this solution is incorrect, as indicated by the red "X" symbol next to it. **Explanation of the Provided Solution Steps:** - The provided solution attempts to evaluate the derivative by showing fractional exponents in terms of \( x \). - The terms \(\frac{-8}{x^{3/2}}\) and \(\frac{10}{x^{1/2}}\) do not relate correctly to the derivative of the function \( f(x) = x^3 \). Let's correctly solve the problem: 1. **Find the derivative of \( f(x) \):** \[ f(x) = x^3 \] \[ \frac{df}{dx} = 3x^2 \] 2. **Evaluate the derivative at \( x = -11 \):** \[ \left. \frac{df}{dx} \right|_{x = -11} = 3(-11)^2 = 3 \cdot 121 = 363 \] So, the correct value of the derivative at \( x = -11 \) is \(\boxed{363}\).
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