Find the indicated complement. Find P(A), given that P(A) 0.675. O 0.838 O 0.675 0.163 0.325
Find the indicated complement. Find P(A), given that P(A) 0.675. O 0.838 O 0.675 0.163 0.325
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
Related questions
Question
![**Find the Indicated Complement**
To calculate the complement of the probability \( P(A) \), given that \( P(A) = 0.675 \), use the formula for the complement:
\[ P(\text{not } A) = 1 - P(A) \]
Given that \( P(A) = 0.675 \),
\[ P(\text{not } A) = 1 - 0.675 = 0.325 \]
**Choices:**
- \( \bigcirc \) 0.838
- \( \bigcirc \) 0.675
- \( \bigcirc \) 0.163
- \( \bullet \) 0.325
The correct answer is **0.325**.
*Explanation:*
The problem provides a multiple-choice question to find the complement of a probability value. The choices are listed along with a marked correct choice (0.325), indicated by a filled-in circle. There is also a reset button for reattempting the question.
**Next Steps: Click "Continue" to proceed.**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F09b63dd4-815c-40b6-89be-26b001693c8f%2F1ace425d-1db3-42fb-b649-eedd85f3bd00%2Foba718q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Find the Indicated Complement**
To calculate the complement of the probability \( P(A) \), given that \( P(A) = 0.675 \), use the formula for the complement:
\[ P(\text{not } A) = 1 - P(A) \]
Given that \( P(A) = 0.675 \),
\[ P(\text{not } A) = 1 - 0.675 = 0.325 \]
**Choices:**
- \( \bigcirc \) 0.838
- \( \bigcirc \) 0.675
- \( \bigcirc \) 0.163
- \( \bullet \) 0.325
The correct answer is **0.325**.
*Explanation:*
The problem provides a multiple-choice question to find the complement of a probability value. The choices are listed along with a marked correct choice (0.325), indicated by a filled-in circle. There is also a reset button for reattempting the question.
**Next Steps: Click "Continue" to proceed.**
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