FInd the Indefinte Integral and check the result by differentlation. 6x dx Step 1 s the derivative of (a-x Let g(x) = (8-x). Observe that-2x Is the dertvatve of Multiply and divide the Integrand by - and rewrite the Integral. 3. 6x (-)-2) de dx = -3 Step 2 Now, g'(x) = Define f(g(x)) = -38 - x)such that f(x) = - Rewrite the glven Integral In terms of g(x). 6x dx = (-2x) dx 8x2 !! f(g(x))g'(x) dx = F(g(x)) + C where F(g(x)) is the antiderivative of f(g(x)).

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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FInd the Indeflnte Integral and check the result by differentlation.
6x
dx
Step 1
2x
-(--*).
Is the dertvative of 8- x
-x]. Let g(x) = (8 -
Observe that
Multiply and divide the Integrand by -
and rewrite the Integral.
6x
dx =
8-x
Step 2
Now, g'(x) =
Define f(g(x)) = -38 – x²]such that Rx) = -3
Rewrite the glven Integral In terms of g(x).
6x
(-2x) dx
%3D
8 x2
- Ho
Rocx))g (x) dx = Fgtx) + C
where F(g(x)) is the antiderivative of f(g(x)).
Transcribed Image Text:FInd the Indeflnte Integral and check the result by differentlation. 6x dx Step 1 2x -(--*). Is the dertvative of 8- x -x]. Let g(x) = (8 - Observe that Multiply and divide the Integrand by - and rewrite the Integral. 6x dx = 8-x Step 2 Now, g'(x) = Define f(g(x)) = -38 – x²]such that Rx) = -3 Rewrite the glven Integral In terms of g(x). 6x (-2x) dx %3D 8 x2 - Ho Rocx))g (x) dx = Fgtx) + C where F(g(x)) is the antiderivative of f(g(x)).
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