Find the horizontal asymptote of the graph of the function. (If an answer does not exist, enter DNE.) x3 - 5x2 + 6x + 1 f(x) x2 – 6x + 5 DNE

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the horizontal asymptote of the graph of the function. (If an answer does not exist, enter DNE.)

\[ f(x) = \frac{x^3 - 5x^2 + 6x + 1}{x^2 - 6x + 5} \]

**Solution:**

The result is displayed in a grey box with "DNE" written inside it, indicating that the horizontal asymptote does not exist for this function.

**Explanation:**

For rational functions, horizontal asymptotes are determined by the degrees of the polynomials in the numerator and the denominator.

- If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \(y = 0\).
- If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is at \(y = \frac{\text{leading coefficient of numerator}}{\text{leading coefficient of denominator}}\).
- If the degree of the numerator is greater than the degree of the denominator, as is the case for this function where the numerator's degree is 3 and the denominator's is 2, there is no horizontal asymptote (denoted as DNE).
Transcribed Image Text:**Problem Statement:** Find the horizontal asymptote of the graph of the function. (If an answer does not exist, enter DNE.) \[ f(x) = \frac{x^3 - 5x^2 + 6x + 1}{x^2 - 6x + 5} \] **Solution:** The result is displayed in a grey box with "DNE" written inside it, indicating that the horizontal asymptote does not exist for this function. **Explanation:** For rational functions, horizontal asymptotes are determined by the degrees of the polynomials in the numerator and the denominator. - If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \(y = 0\). - If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is at \(y = \frac{\text{leading coefficient of numerator}}{\text{leading coefficient of denominator}}\). - If the degree of the numerator is greater than the degree of the denominator, as is the case for this function where the numerator's degree is 3 and the denominator's is 2, there is no horizontal asymptote (denoted as DNE).
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