Find the general term of the sequence, starting withn = 1, determine whether the sequence converges, and if so find its limit. 2 3 4 32 – 12' 42 – 2²² 5² – 32 n+1 , sequence converges to an n2 - (n + 2)2 , sequence converges to an = (п + 2)? — п? 4° n+1 an = , sequence converges to 0. (п + 2)? — п2 n+1 , sequence does not converge. an = (п + 2)2 — п2 n+1 , sequence converges to (n + 2)? – n² o o
Find the general term of the sequence, starting withn = 1, determine whether the sequence converges, and if so find its limit. 2 3 4 32 – 12' 42 – 2²² 5² – 32 n+1 , sequence converges to an n2 - (n + 2)2 , sequence converges to an = (п + 2)? — п? 4° n+1 an = , sequence converges to 0. (п + 2)? — п2 n+1 , sequence does not converge. an = (п + 2)2 — п2 n+1 , sequence converges to (n + 2)? – n² o o
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:Find the general term of the sequence, starting with n = 1, determine whether the sequence converges, and if so find its limit.
2
3
4
32 – 12' 42 - 22' 52
32
n +1
1
sequence converges to
n2 - (n + 2)2
, sequence converges to
An =
(п + 2)2 - п?
n +1
, sequence converges to 0.
= "p
(п + 2)2 — п2
n+1
, sequence does not converge.
an =
(п + 2)2 — п2
n + 1
an =
(п + 2)? -п2
sequence converges to
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