Find the general solution using separationof variables y = re" y = 5ry – 2r Solve r dy = y +1 and find the particular solution when y(1) = 1 dr ip dr ry %3D r+1 Solve and find the particular solution when y(1) = 3 %3D = e+2y (I + x)_ P z sin? y. = (r + 1)? dr dy Solve y dy =z and find the particular solution when y(0) = 1 dr %3! y = y - " (1+z*) + ry = 0 dy = eV dx dy 3y – x- | %3D dr 1 xy +y dy cos(x) dy = y? - 1 dr dy 2y cos(r) 1+ sin(x) dy 1 dr y? dx dx 3y?

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