Find the general solution of x (y + 1) dx + y² (x – 1) dy = 0 х2 - у? + 2х - 2у + C. 2ln[(y + 1)/(x - 1)] = C 2х + 2y + D. 2ln[(y + 1)/(x - 1)] = C x2 + y? - 2x - 2y + 2ln[(y + 1)/(x - 1)] = C x2 + y? + 2x - 2y + 2ln[(y + 1)/(x - 1)] = C А. %3D x? + y? В.
Find the general solution of x (y + 1) dx + y² (x – 1) dy = 0 х2 - у? + 2х - 2у + C. 2ln[(y + 1)/(x - 1)] = C 2х + 2y + D. 2ln[(y + 1)/(x - 1)] = C x2 + y? - 2x - 2y + 2ln[(y + 1)/(x - 1)] = C x2 + y? + 2x - 2y + 2ln[(y + 1)/(x - 1)] = C А. %3D x? + y? В.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Find the general solution of x² (y + 1) dx + y² (x – 1) dy = 0
x2 - у? + 2х — 2у +
А.
2ln[(y + 1)/(x - 1)] = C
х? + у? - 2х - 2у +
С.
2ln[(y + 1)/(x - 1)] = C
х? + у2 + 2х - 2у +
x² + y? - 2x + 2y +
В.
2ln[(y + 1)/(x - 1)] = C
D.
2ln[(y + 1)/(x - 1)] = C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F469887fc-5ad8-4b0c-8121-d6405cfd199e%2F5d01b529-bacb-4913-8d18-4c3d7cae24bc%2Fcdip94_processed.png&w=3840&q=75)
Transcribed Image Text:Find the general solution of x² (y + 1) dx + y² (x – 1) dy = 0
x2 - у? + 2х — 2у +
А.
2ln[(y + 1)/(x - 1)] = C
х? + у? - 2х - 2у +
С.
2ln[(y + 1)/(x - 1)] = C
х? + у2 + 2х - 2у +
x² + y? - 2x + 2y +
В.
2ln[(y + 1)/(x - 1)] = C
D.
2ln[(y + 1)/(x - 1)] = C
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