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Find the general solution of the given system of equations. O O C O X = C1 X = C1 X = C1 X = C1 X = C1 7 cost- cost 7 cost- sint sint cost 7 cost - sint cost 7 cost - sint - cost 7 cost- sint - cost + C₂ + C₂ + C₂ + C₂ + c₂ 7 sint 50 = (₁-59 ) x + (-i) -7 sint x' = 7 sint + cost sint 7 sint + cost sint 7 sint + cost sint 7 sint - cost - sint - cost - sint (7) 1 + -4(2) -7 (7) - 7(1) 2 2 -7 (7) 2 + 72 - NN NN NN t cost cost- t cost t cost + 1 t cost + 2 1 51 4 (SD) 7 1 2 (17)₁ (3) (1) ¹1 (1) ¹ 2 1 2 t sint sint t sint t sint t sint (2) 1 4 1 4 1 4 (2) 2 cost - cost cost - 1 4 1 51 (5) 7 4 1 4 sint 51 (5¹) ₁ t 7 51 (1) sin 7

Find the general solution of the given system of equations. O O C O X = C1 X = C1 X = C1 X = C1 X = C1 7 cost- cost 7 cost- sint sint cost 7 cost - sint cost 7 cost - sint - cost 7 cost- sint - cost + C₂ + C₂ + C₂ + C₂ + c₂ 7 sint 50 = (₁-59 ) x + (-i) -7 sint x' = 7 sint + cost sint 7 sint + cost sint 7 sint + cost sint 7 sint - cost - sint - cost - sint (7) 1 + -4(2) -7 (7) - 7(1) 2 2 -7 (7) 2 + 72 - NN NN NN t cost cost- t cost t cost + 1 t cost + 2 1 51 4 (SD) 7 1 2 (17)₁ (3) (1) ¹1 (1) ¹ 2 1 2 t sint sint t sint t sint t sint (2) 1 4 1 4 1 4 (2) 2 cost - cost cost - 1 4 1 51 (5) 7 4 1 4 sint 51 (5¹) ₁ t 7 51 (1) sin 7

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the general solution of the given system of equations. X = C1 X = C1 X = C1 X = C1 X = C1 7 cost sint ( cost 7 cost sint (70 (² (² (² cost 7 cost sint cost 7 cost sint - cost 7 cost - sint - cost + C₂ 2( + C₂ + C2 2 (² + C₂ 7 sint + cost sint 7 sint + cost sint 7 sint + cost sint + C₂ ( (² cost X' x = (₁ - ) x + (-200²) 7 50 -7 sint 7 sint - 7 sint cost - sint 7 ) + ² (7) cost - 1 (7) sinr ₁ t t 2 2 7 ¹) ½ - (2) Cust- cost - sint cost + 7 7 (2) 2 7 ') - ² (7) 2 7 - (7) 2 t cost 4 t cost + 1 t cost + 51 (¹) sin 7 1 ½ (7) 2 1 7 (6) 2 7 ¹1 (1) 2 t sint t sint t sint 7 4 2 1 51 +7 (2) cost - ² (¹) ₁ t 4 7 - 1 4 (51) cost sint 7 1 51 (2) cost - (¹¹) sint
Transcribed Image Text:Find the general solution of the given system of equations. X = C1 X = C1 X = C1 X = C1 X = C1 7 cost sint ( cost 7 cost sint (70 (² (² (² cost 7 cost sint cost 7 cost sint - cost 7 cost - sint - cost + C₂ 2( + C₂ + C2 2 (² + C₂ 7 sint + cost sint 7 sint + cost sint 7 sint + cost sint + C₂ ( (² cost X' x = (₁ - ) x + (-200²) 7 50 -7 sint 7 sint - 7 sint cost - sint 7 ) + ² (7) cost - 1 (7) sinr ₁ t t 2 2 7 ¹) ½ - (2) Cust- cost - sint cost + 7 7 (2) 2 7 ') - ² (7) 2 7 - (7) 2 t cost 4 t cost + 1 t cost + 51 (¹) sin 7 1 ½ (7) 2 1 7 (6) 2 7 ¹1 (1) 2 t sint t sint t sint 7 4 2 1 51 +7 (2) cost - ² (¹) ₁ t 4 7 - 1 4 (51) cost sint 7 1 51 (2) cost - (¹¹) sint
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