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Find the general solution of the given differential equation using variation of parameters. + 4y = sec2t, - <1< 4 O y = c1 + c2cos2t + c3 sin2t + 0.1251ln|sec2t + tan2r| – 0.25tcos2t + 0.125sin2fln(cos2f) O y = c1 + c2cos2t + c3 sin2t + c4ln|sec2t + tan2t| – cstcos2t + c5sin2tln(cos2t) O y = 1 + cos2t + sin2t + c¡ In|sec2t + tan2t| – c2tcos2t + c3 sin2tln(cos2t) O y = c1 + c2cos2t + c3 sin2t + 0.125ln|sec2t + tan2t| – 0.25t + 0.125ln(cos2f)

Find the general solution of the given differential equation using variation of parameters. + 4y = sec2t, - <1< 4 O y = c1 + c2cos2t + c3 sin2t + 0.1251ln|sec2t + tan2r| – 0.25tcos2t + 0.125sin2fln(cos2f) O y = c1 + c2cos2t + c3 sin2t + c4ln|sec2t + tan2t| – cstcos2t + c5sin2tln(cos2t) O y = 1 + cos2t + sin2t + c¡ In|sec2t + tan2t| – c2tcos2t + c3 sin2tln(cos2t) O y = c1 + c2cos2t + c3 sin2t + 0.125ln|sec2t + tan2t| – 0.25t + 0.125ln(cos2f)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the general solution of the given differential equation using variation of parameters. + 4y = sec2t, - <1 < 4 O y = c1 + c2cos2t + c3 sin2t + 0.1251ln|sec2t + tan2r| – 0.25tcos2t + 0.125sin2fln(cos2f) O y = c1 + c2cos2t + c3 sin2t + c4ln|sec2t + tan2t| – cztcos2t + c6 sin2tln(cos2t) O y = 1 + cos2t + sin2t + c¡ In|sec2t + tan2t| – c2tcos2t + c3 sin2tln(cos2t) O y = c1 + c2cos2t + c3 sin2t + 0.125ln|sec2t + tan2t| – 0.25t + 0.125ln(cos2f)
Transcribed Image Text:Find the general solution of the given differential equation using variation of parameters. + 4y = sec2t, - <1 < 4 O y = c1 + c2cos2t + c3 sin2t + 0.1251ln|sec2t + tan2r| – 0.25tcos2t + 0.125sin2fln(cos2f) O y = c1 + c2cos2t + c3 sin2t + c4ln|sec2t + tan2t| – cztcos2t + c6 sin2tln(cos2t) O y = 1 + cos2t + sin2t + c¡ In|sec2t + tan2t| – c2tcos2t + c3 sin2tln(cos2t) O y = c1 + c2cos2t + c3 sin2t + 0.125ln|sec2t + tan2t| – 0.25t + 0.125ln(cos2f)
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