Find the general solution of the following equation valid near the origin: (1+4x2)y"-8y=0 00 y=ag(1-4²) + √(x-2-2-2-2-1] k=1 4k²-1 O Option 1 =a₂(1+4x²) + a√[x+ £² O Option 3 **] (-1)+1₂+1 44²-1 y=a(1−4x²)+a][x+ (−1)²2%; * +1] 222- 4k²-1 Option 2 00 3+²√x-² _y=a₁(1+4x²)+a₁ Option 4 22x2+1 4k2 1
Find the general solution of the following equation valid near the origin: (1+4x2)y"-8y=0 00 y=ag(1-4²) + √(x-2-2-2-2-1] k=1 4k²-1 O Option 1 =a₂(1+4x²) + a√[x+ £² O Option 3 **] (-1)+1₂+1 44²-1 y=a(1−4x²)+a][x+ (−1)²2%; * +1] 222- 4k²-1 Option 2 00 3+²√x-² _y=a₁(1+4x²)+a₁ Option 4 22x2+1 4k2 1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Find the general solution of the following equation valid near the origin:
(1+4x2)y"-8y=0
00
y=ag(1-4²) + √(x-2-2-2-2-1]
k=1 4k²-1
O Option 1
=a₂(1+4x²) + a√[x+ £²
O Option 3
**]
(-1)+1₂+1
44²-1
y=a(1−4x²)+a][x+ (−1)²2%; * +1]
222-
4k²-1
Option 2
00
3+²√x-²
_y=a₁(1+4x²)+a₁
Option 4
22x2+1
4k2
1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8125e78e-cb90-4f62-b2bd-c75f18dfa9c3%2Fe571d12b-3c0c-45f3-8a6d-2d36b874a874%2F3r8q1p_processed.png&w=3840&q=75)
Transcribed Image Text:Find the general solution of the following equation valid near the origin:
(1+4x2)y"-8y=0
00
y=ag(1-4²) + √(x-2-2-2-2-1]
k=1 4k²-1
O Option 1
=a₂(1+4x²) + a√[x+ £²
O Option 3
**]
(-1)+1₂+1
44²-1
y=a(1−4x²)+a][x+ (−1)²2%; * +1]
222-
4k²-1
Option 2
00
3+²√x-²
_y=a₁(1+4x²)+a₁
Option 4
22x2+1
4k2
1
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