find the general solution by finding the homogeneous solution and a particular solution. 1) y" + 4y' = x and the correct answer is y = c1 + c2e^(-4x) + 1/8(x^2) - 1/16. can you please show me how to get to the correct answer? so we can seek a solution of the form yp = =Ax + B
find the general solution by finding the homogeneous solution and a particular solution.
1) y" + 4y' = x
and the correct answer is y = c1 + c2e^(-4x) + 1/8(x^2) - 1/16. can you please show me how to get to the correct answer?
so we can seek a solution of the form yp = =Ax + B
Given information:
The differential equation:
To find:
The general solution by finding the homogeneous solution and a particular solution.
Concept used:
We will solve this second-order linear differential equation by first finding the homogeneous solution and then adding a particular solution. The homogeneous solution solves the equation without the non-homogeneous term (in this case, the
on the right-hand side), and the particular solution deals with the non-homogeneous term.
Step by step
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