Find the function g(x) satisfying the two conditions: 1. g'(x) =-512x³ 2. The maximum value of g(x) is 5. 9(x) = ☐

Q: If f(x) = (2x2 – 5)(2x + 2), find f '(x).

A:

Q: Find f (x) if f'(x) = 3x² + 4x + 1 and f (2) = 21. f (x)

A:

Q: f(x)=1/x+7 f-1(x)=

A: Given function is

Q: find the extrema (minimum and maximum) of f(x) = x2-1 on (-1,2). If none, explain why.

A:

Q: Find f. f"(x) = 4 + 6x + 24x², f(0) = 2, f(1) = 11 f(x)

A: Just integrating given equation twice and then find the value of integration constant with the help…

Q: Find f. f"(x) = 8 + 6x + 24x², f(0) = 5, f(1) = 15 f(x)

A: Find your answer below

Q: Find f"(x). f(x) = 3x² – 14x– %D f"(x) =| %3D

A:

Q: Find F-7(x) for f(x)= 13 +14x

A:

Q: Find f-1(x) for the function. х f(x) %3D x + 1 f-1(x) =

A:

Q: f(x) = x+ 4/x

A:

Q: Differentiate. f(x) %3Dx =x° +x' d dx (x)] =

A: ddxxn = n·xn-1

Q: find the interval where the function is increasing or decreasing  f(x) = 6/x-4

A: Function is not defined at x=4  there are two intervals where the function is defined   ( -∞,4 ) and…

Q: f(X) = 2/X       g(X) = X+1/9     (What is the domain?)

A:

Q: Use the graph of f(x) = 1/x2 to graph g(x) = 1/(x - 2)2 + 1.

A: fx=1x2, gx=1x-22+1 Now the graph of fx=1x2 is,

Q: f (5), where f (x) = 1/(2x).

A: Given fx=12x we have to find f(5)

Q: Let f(x)= 2/x-3. Let g(x)= 5/x+2. Determine (f/g)(x)

A: See the attached file

Q: Find f(x) if f (x) = x/x given f(1) = 2. %3D

A: