Find the following probability for the standard normal random variable z. e. P(z 20) f. P(-2.54 szs1.35) g. P(z> - 2.15) h. P(z< 2.15) a. P(z>1.15) b. P(z< - 1.83) c. P(0.01szs2.63) d. P(-1.981.15) = .125 (Round to three decimal places as needed.) b. P(z< -1.83) = .034 (Round to three decimal places as needed.) c. P(0.01szs2.63) = .492 (Round to three decimal places as needed.) d. P(-1.98 sz< - 0.64) =|(Round to three decimal places as needed.)
Find the following probability for the standard normal random variable z. e. P(z 20) f. P(-2.54 szs1.35) g. P(z> - 2.15) h. P(z< 2.15) a. P(z>1.15) b. P(z< - 1.83) c. P(0.01szs2.63) d. P(-1.981.15) = .125 (Round to three decimal places as needed.) b. P(z< -1.83) = .034 (Round to three decimal places as needed.) c. P(0.01szs2.63) = .492 (Round to three decimal places as needed.) d. P(-1.98 sz< - 0.64) =|(Round to three decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
D through H
![**Finding Probabilities for Standard Normal Random Variable Z**
Given the following probabilities for the standard normal random variable \( z \):
a. \( P(z > 1.15) \)
b. \( P(z < -1.83) \)
c. \( P(0.01 \leq z \leq 2.63) \)
d. \( P(-1.98 \leq z < -0.64) \)
e. \( P(z \geq 0) \)
f. \( P(-2.54 \leq z \leq 1.35) \)
g. \( P(z \geq -2.15) \)
h. \( P(z < 2.15) \)
**Calculated Probabilities:**
a. \( P(z > 1.15) = 0.125 \) (Round to three decimal places as needed.)
b. \( P(z < -1.83) = 0.034 \) (Round to three decimal places as needed.)
c. \( P(0.01 \leq z \leq 2.63) = 0.492 \) (Round to three decimal places as needed.)
d. \( P(-1.98 \leq z < -0.64) = \) [Blank, round to three decimal places as needed.]
_Note: Explore statistical tables or software to find the probabilities for any remaining parts._](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F40766f6b-1d39-4de4-8cc4-4220165d991f%2F42316abc-1962-4c04-9b0c-ec939c850ea3%2Fdfh6slt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Finding Probabilities for Standard Normal Random Variable Z**
Given the following probabilities for the standard normal random variable \( z \):
a. \( P(z > 1.15) \)
b. \( P(z < -1.83) \)
c. \( P(0.01 \leq z \leq 2.63) \)
d. \( P(-1.98 \leq z < -0.64) \)
e. \( P(z \geq 0) \)
f. \( P(-2.54 \leq z \leq 1.35) \)
g. \( P(z \geq -2.15) \)
h. \( P(z < 2.15) \)
**Calculated Probabilities:**
a. \( P(z > 1.15) = 0.125 \) (Round to three decimal places as needed.)
b. \( P(z < -1.83) = 0.034 \) (Round to three decimal places as needed.)
c. \( P(0.01 \leq z \leq 2.63) = 0.492 \) (Round to three decimal places as needed.)
d. \( P(-1.98 \leq z < -0.64) = \) [Blank, round to three decimal places as needed.]
_Note: Explore statistical tables or software to find the probabilities for any remaining parts._
Expert Solution
Step 1
We have given that
X~N( 0 , 1)
μ = 0 , ? = 1
Z-score =( x - μ )/?
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