Find the following probability for the standard normal random variable z. a. P(z >1.15) b. P(z < - 1.93) c. P(0.76 szs2.98) d. P(-1.05 sz< - 0.04) e. P(z 20) f. P(-2.41szs1.89)

Q: Solve for 0. 48 18

A:

Q: Solve for the variable P to two decimal places. 54,000 = P0.087(12) P= (Round to two decimal places…

A:

Q: Solve. 27(9) 32x+34 = 16 X= Round to 4 decimal places.

A:

Q: L 14 Solve for x. X = 15 20 3x X

A:

Q: Solve for m. -3+m = 10          /9

A: To solve for m

Q: Solve A = 4Tr2 for r

A:

Q: 2. Solve for B. 30m 18m 22m

A: It is given that,            We have to find B.

Q: Solve K= PRT for P. P=

A:

Q: Solve for the variable P to two decimal places. 77,000 = P0.084(6) P= (Round to two decimal places…

A: 77000=Pe0.0846

Q: 1. Solve for x. 3. 540

A:

Q: 2. Solve undetermine u8Bicent

A:

Q: This equation shows how the cost of a charity gala depends on the number of attendees. d = 6a + 30…

A: Given that  The cost of a charity gala depends on the number of attendees. d=6a+30 To find the…

Q: Solve for x: 16 O8 O 26.7 O 9.6

A:

Q: 2sin z + 5.20s z = 7

A:

Q: w=ac/n  , solve for n

A:

Q: solve for x.6x−2 = 36

A:

Q: Solve for t. Round the answer to three decimal places. 5e2t=15

A:

Q: Solve for x. 39

A: If a tangent and a secant are drawn to a circle from an exterior point, then the square of the…

Q: 981 = 500e0.30 %3D

A:

Q: Solve for X. If necessary, round your answer to 4 significant digits. 4.155x³ = -2482 I

A:

Q: Solve the initial vadue probdem. -2

A:

Q: Solve using Order of Operations 13 x 32 = %3D

A:

Q: EK+L=D-UK Solve for K

A: The given equation is EK+L=D-UK.

Q: Solve for X. If necessary, round your answer to 4 significa

A: Introduction: The definition of a quadratic as a second-degree polynomial equation implies that at…