Find the following probabilities for the standard normal random variable z: (a) P(-0.87 \leq z \leq 1.63 ) = (b) P(-1.22 \leq z \leq 1.74 ) = (c) P(z \leq 1.06 ) = (d) P(z > -0.41 ) =
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Find the following probabilities for the standard normal random variable z:
(a) P(-0.87 \leq z \leq 1.63 ) =
(b) P(-1.22 \leq z \leq 1.74 ) =
(c) P(z \leq 1.06 ) =
(d) P(z > -0.41 ) =
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- Two students are taking a college entrance exam and known to have a normal distribution of scores. Both students receive raw scores of 60 and 97, which correspond to z scores (often called the standardized scores) of -1.5 and 3 respectively. Answer the followings: (a) Denote the normal probability distribution of the raw exam scores. (b) Calculate the value of mean for the distribution of raw exam scores. (c) Calculate the value of standard deviation of the raw exam scores.If the random variable X is normally distributed with a mean equal to .45 and a standard deviation equal to .40, then P(X ≥ .75) is: (a) 0.2266 (b) 0.4525 (c) 0.7734 (d) 0.7500 (e) None of the abovePorphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a random variable that represents the number of milligrams of porphyrin per deciliter of blood. In healthy circles, x is approximately normally distributed with mean ? = 43 and standard deviation ? = 9. Find the following probabilities. (a) x is less than 60(b) x is greater than 16(c) x is between 16 and 60(d) x is more than 60
- If XX represents a random variable coming from a normal distribution and P(X<10.2)=0.22P(X<10.2)=0.22, then P(X>10.2)=0.78P(X>10.2)=0.78. true or falseSuppose a life insurance company sells a $170,000 1-year term life insurance policy to a 20-year-old female for $170. According to the National Vital Statistics Report, 58(21), the probability that the female survives the year is 0.999544. The expected value of this policy to the insurance company is $92.48. What is the standard deviation of the value of the life insurance policy? Why is the value so high?The time taken by employees at Grace Floral shop to put a bouquet together has a normal distribution with mean 26.4 minutes and standard deviation .8 minutes. (i) Find the probability that an employee chosen at random takes between 24.6 and 27.8 minutes to put a bouquet together. [5] (ii) 12% of employees take more than t minutes to put a bouquet together. (ii) Find the value of t.
- A machine produces small rods and large rods. The diameters of small rods are normally distributed with mean 2 cm and standard deviation 0.12 cm. The diameters of large rods are normally distributed with mean 2.2 cm and standard deviation 0.15 cm. (i) Find the probability that a randomly chosen small rod has diameter greater than 2.15 cm. (ii) A box contains one small rod and one large rod. Find the probability that at least one of the rods has diameter greater than 2.15 cm.I just need help with (d) and (e)The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.7 minutes and a standard deviation of 3.5 minutes. Assume that the distribution of taxi and takeoff times is approximately normal. You may assume that the jets are lined up on a runway so that one taxies and takes off immediately after the other, and that they take off one at a time on a given runway. (a) What is the probability that for 33 jets on a given runway, total taxi and takeoff time will be less than 320 minutes? (Round your answer to four decimal places.)(b) What is the probability that for 33 jets on a given runway, total taxi and takeoff time will be more than 275 minutes? (Round your answer to four decimal places.)(c) What is the probability that for 33 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes? (Round your answer to four decimal places.)
- 'Melanoma' is a form of skin cancer and each year 17% of the patients who suffer from the disease die. A random sample of 10,000 melanoma patients is formed at the start of a year. Let Y denote the number of patients in this sample who will die during the year? (a) What is the expected value of Y? That is, compute E(Y). Answer: [Select] (b) What is the variance of Y? That is, compute var(Y). Answer: [Select] (c) What is the probability that Y exceeds 1,800? That is, compute P(Y> 1,800). Answer: [Select]The time taken by employees at Grace Floral shop to put a bouquet together has a normal distribution with mean 27.5 minutes and standard deviation 1.5 minutes. (i) Find the probability that an employee chosen at random takes more than 29 minutes to put a bouquet together. (ii) 25% of employees take more than t minutes to put a bouquet together. Find the value of t.Please solve practice question 2 and show the steps for the required areas. Please and thank you.
