Find the focus by drawing a ray diagram using the position of source S and the image S'given in the fig.-Q(5). (AS,) N, N, S' fig- Q(5)
Q: n the basis of above ray diagram/information fill in the blanks. ) The position of object AB would…
A: The ray diagram is shown as,
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A: Please see the answer in Step 2 Note: I have answered the first question only in accordance with the…
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Q: LENS Converging Diverging 2f f 2f Focal Length : 27.5 cm focus Object Distance : 80 cm Object Height…
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Q: Inced help drawing a converging mirron /R=10f%3D5 do=15 di=7.5 R=10 ho= - 2 his-l M= -.5 %3D
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Q: What is the object distance in centimeter for a person whose eyes have a power of 51.03 diopter?…
A: given,image distance=0.02mpower, P=51.03D=1f
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A: In this problem we will use snells law of refraction μ1sinθ1=μ2sinθ2
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Q: from the image the net potential at the P point due to 4 chorged particde 15 Is e qual to how much…
A: Given that:q=9.00×10-15 Cd=4.00 cm=0.04 m To determine the potential at P.
Q: 5) An image is formed 15 cm behind a 10-cm-focal-length converging lens. Find the object distance a)…
A: Given:Focal length of a converging lens, f = 10 cmImage distance = 15 cm behind the lens
Q: Suppose a certain person's visual acuityis such+hat he can see objects ciear Hthat torm an image…
A: Given Height of image (hi) = 4.25 μm = 4.25×10-6 m Height of object ho…
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A: We will use lens formula and then formula to calculate magnification. Object distance is negative…
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A: The position vector of the point C and the vector for force P can be written as,
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A: The bending of light hen it travels from one medium to another medium is called refraction.When…
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A: The index of refraction of oil is noil=1.15. The index of refraction of water is nwater=1.33. Assume…
Q: What is the object distance in centimeter for a person whose eyes have a power of 52.07 diopter?…
A: Answer :- Power of a lens (P) = 52.07 D Power of a lens (P) = 1/ focal length (f) in meter P = 1/f…
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Q: 45° a? 90° 45° B? 45°
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Q: Suppose a certain person's visual acuityis suchmat he can see objects ciear M that torm an image…
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Q: Con vaA The Virtual imoge prodlucter g mioror is one-third the Size of the oójéet. a) 4 the object…
A: The u-v-f relation for a spherical mirror(concave/convex) is 1v+1u=1f ....(1) The…
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A: The refractive index of incident medium, air is 1.0003, and the refractive index of glass is 1.52.
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A: Given values:- Near point,(NP)=55 cm ----(1) Book Distance,(BP)=28 cm ----(2) Lens eye…
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A: The radius of the curvature is
Q: 3.83 √√ = /[6.1 1.57 6.18 sin (wt -0.756) - 23.8e-wt/0.943 d d(wt)
A: Given the integral is 1π∫1.573.836.18sinωt-0.756-23.8e-ωt0.9432dωt We have to solve the given…
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A: Step1: Definition of magnification of Telescope. Magnification equation of telescope m = fofe here…
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A: In this question, the given area can be subdivided into the three separate subareas; 1. Rectangle 2.…
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Q: placed 20 em apart, as shown object 30 5TWO converging lenges ave Figure, with in below the left. a)…
A: Given,
Q: 11. (II) An object 3.0 mm high is placed 16 cm from a convex mirror of radius of curvature 16 cm.…
A: Given: Object height, 3 mm Radius of curvature, 16 cm Object distance, 16 cm To find: a) Ray tracing…
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Q: Two points white doß are 2mm about on a black paper. They are niewed by eye of pupil diameter 2.5mm.…
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Q: 2. (a) (b) A spherical concave mirror has a radius of curvature of 65 cm. An object is placed 40 cm…
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