Find the first partial derivatives of 2х — у f(x, y) = 2x + у of Әх -(3,4) = of -(3,4) = ду at the point (x, y) = (3,4).

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the first partial derivatives of
2х — у
_f(x, y) :
2x + у
af
дх
- (3, 4) =
=
af
ду
·(3, 4) =
at the point (x, y) = (3,4).
Transcribed Image Text:Find the first partial derivatives of 2х — у _f(x, y) : 2x + у af дх - (3, 4) = = af ду ·(3, 4) = at the point (x, y) = (3,4).
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