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Find the first-order partial derivatives of: z = 40x2 + 29x²y2 + 6y² дz дz ( А. = 80 + 58y²; = 58y + 12 Әх ду дz О) в. = 80x + 58xy2 58x2y +12 дх дz ду дz О C. az = 80x+58xy; 1 = 58xy +12у ?х о D. Əz = 80x + 58x²y, 1 = 58xy+12y ах ду

Find the first-order partial derivatives of: z = 40x2 + 29x²y2 + 6y² дz дz ( А. = 80 + 58y²; = 58y + 12 Әх ду дz О) в. = 80x + 58xy2 58x2y +12 дх дz ду дz О C. az = 80x+58xy; 1 = 58xy +12у ?х о D. Əz = 80x + 58x²y, 1 = 58xy+12y ах ду

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the first-order partial derivatives of: z = 40x2 + 29x²y2 + 6y² дz дz ; 58y + 12 ?х ду О А. B. дz ?х ах D. az ?х = 80+ 58y² = 80x + 58xy? = i дз = 80x + 58xу ау = дz ду = = дz 80x + 58x²y, y 58x2y + 12 у 58xy +12y = 58xy +12y
Transcribed Image Text:Find the first-order partial derivatives of: z = 40x2 + 29x²y2 + 6y² дz дz ; 58y + 12 ?х ду О А. B. дz ?х ах D. az ?х = 80+ 58y² = 80x + 58xy? = i дз = 80x + 58xу ау = дz ду = = дz 80x + 58x²y, y 58x2y + 12 у 58xy +12y = 58xy +12y
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