Find the first derivative f' and the original function f. f"(x) = x³ – 18x, f' (1) = 0, ƒ(1) = 8 (Use symbolic notation and fractions where needed.) 35 f'(x) = 4 9x3 41 35x f(x) = %3D 20 3. 4 20

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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f’x is correct, but the second one (f(x)), keeps showing its the wrong answer. I’m not sure what I did wrong. Thank you
**Problem Statement:**

Find the first derivative \( f' \) and the original function \( f \).

Given:
\[ f'''(x) = x^3 - 18x \]
\[ f'(1) = 0 \]
\[ f(1) = 8 \]

(Use symbolic notation and fractions where needed.)

---

**Solution:**

1. **First Derivative:**

   The first derivative \( f'(x) \) is:

   \[
   f'(x) = \frac{x^4}{4} - 9x^2 + \frac{35}{4}
   \]

2. **Original Function:**

   The original function \( f(x) \) is:

   \[
   f(x) = \frac{x^5}{20} - \frac{9x^3}{3} + \frac{35x}{4} + \frac{41}{20}
   \]
Transcribed Image Text:**Problem Statement:** Find the first derivative \( f' \) and the original function \( f \). Given: \[ f'''(x) = x^3 - 18x \] \[ f'(1) = 0 \] \[ f(1) = 8 \] (Use symbolic notation and fractions where needed.) --- **Solution:** 1. **First Derivative:** The first derivative \( f'(x) \) is: \[ f'(x) = \frac{x^4}{4} - 9x^2 + \frac{35}{4} \] 2. **Original Function:** The original function \( f(x) \) is: \[ f(x) = \frac{x^5}{20} - \frac{9x^3}{3} + \frac{35x}{4} + \frac{41}{20} \]
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