Find the exact value of each of the remaining trigonometric functions of 0. Rationalize denominators when applicable. √√5 cot 0 = given that is in quadrant I " 6

Trigonometry (MindTap Course List)
8th Edition
ISBN:9781305652224
Author:Charles P. McKeague, Mark D. Turner
Publisher:Charles P. McKeague, Mark D. Turner
Chapter2: Right Triangle Trigonometry
Section: Chapter Questions
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**Task:**
Find the exact value of each of the remaining trigonometric functions of \( \theta \). Rationalize denominators when applicable.

Given: 
\[ \cot \theta = \frac{\sqrt{5}}{6} \]
\[ \theta \text{ is in quadrant I} \]

**Solution Overview:**

To solve this problem, we need to find the values of the remaining trigonometric functions: sin(θ), cos(θ), tan(θ), sec(θ), and csc(θ). Given that cot(θ) is in the first quadrant, we know that all trigonometric functions will be positive.

**Steps to Find the Remaining Trigonometric Functions:**

1. **Assign Variables for Trigonometric Values:**

\[ \cot \theta = \frac{\cos \theta}{\sin \theta} \]
From the given problem:
\[ \cot \theta = \frac{\sqrt{5}}{6} \]

2. **Assign \( \cos \theta = \sqrt{5} \) and \( \sin \theta = 6 \):**

Let's keep these values and use the Pythagorean identity to find the hypotenuse (r).

3. **Finding the Hypotenuse Using Pythagorean Theorem:**

\[ r = \sqrt{\cos^2 \theta + \sin^2 \theta} \]

Substituting \(\cos \theta \) and \(\sin \theta \):
\[ r = \sqrt{(\sqrt{5})^2 + (6)^2} = \sqrt{5 + 36} = \sqrt{41} \]

4. **Calculate the Remaining Trigonometric Values:**

- **sin(θ):**
\[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{6}{\sqrt{41}} \]

- **cos(θ):**
\[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{\sqrt{5}}{\sqrt{41}} \]

- **tan(θ):**
\[ \tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{6}{\sqrt{5}} \]

- **csc(θ):**
\[ \csc \theta = \frac{1}{\sin \
Transcribed Image Text:**Task:** Find the exact value of each of the remaining trigonometric functions of \( \theta \). Rationalize denominators when applicable. Given: \[ \cot \theta = \frac{\sqrt{5}}{6} \] \[ \theta \text{ is in quadrant I} \] **Solution Overview:** To solve this problem, we need to find the values of the remaining trigonometric functions: sin(θ), cos(θ), tan(θ), sec(θ), and csc(θ). Given that cot(θ) is in the first quadrant, we know that all trigonometric functions will be positive. **Steps to Find the Remaining Trigonometric Functions:** 1. **Assign Variables for Trigonometric Values:** \[ \cot \theta = \frac{\cos \theta}{\sin \theta} \] From the given problem: \[ \cot \theta = \frac{\sqrt{5}}{6} \] 2. **Assign \( \cos \theta = \sqrt{5} \) and \( \sin \theta = 6 \):** Let's keep these values and use the Pythagorean identity to find the hypotenuse (r). 3. **Finding the Hypotenuse Using Pythagorean Theorem:** \[ r = \sqrt{\cos^2 \theta + \sin^2 \theta} \] Substituting \(\cos \theta \) and \(\sin \theta \): \[ r = \sqrt{(\sqrt{5})^2 + (6)^2} = \sqrt{5 + 36} = \sqrt{41} \] 4. **Calculate the Remaining Trigonometric Values:** - **sin(θ):** \[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{6}{\sqrt{41}} \] - **cos(θ):** \[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{\sqrt{5}}{\sqrt{41}} \] - **tan(θ):** \[ \tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{6}{\sqrt{5}} \] - **csc(θ):** \[ \csc \theta = \frac{1}{\sin \
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