Find the exact length of the curve. y = 1 + 8x3/2, 0sxs1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the exact length of the curve for the given function.

**Function:**

\[ y = 1 + 8x^{3/2} \]

**Interval:**

\[ 0 \leq x \leq 1 \]

**Solution Approach:**

To find the exact length of the curve, we will use the arc length formula for a curve defined by \( y = f(x) \) on the interval \([a, b]\):

\[ L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \]

1. **Differentiate the Function:**

   Find the derivative \(\frac{dy}{dx}\) of the given function \( y = 1 + 8x^{3/2} \).

2. **Set Up the Integral:**

   Substitute the derivative into the arc length formula and calculate the integral:

   \[ L = \int_{0}^{1} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \]

This approach will yield the exact length of the curve from \( x = 0 \) to \( x = 1 \).
Transcribed Image Text:**Problem Statement:** Find the exact length of the curve for the given function. **Function:** \[ y = 1 + 8x^{3/2} \] **Interval:** \[ 0 \leq x \leq 1 \] **Solution Approach:** To find the exact length of the curve, we will use the arc length formula for a curve defined by \( y = f(x) \) on the interval \([a, b]\): \[ L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \] 1. **Differentiate the Function:** Find the derivative \(\frac{dy}{dx}\) of the given function \( y = 1 + 8x^{3/2} \). 2. **Set Up the Integral:** Substitute the derivative into the arc length formula and calculate the integral: \[ L = \int_{0}^{1} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \] This approach will yield the exact length of the curve from \( x = 0 \) to \( x = 1 \).
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