Answer in writing on paper, please. Thank you! ### Trigonometric Functions: Exact Angle Measures and Side LengthsFind the exact angle measure (in radians) or side length for each of the following problems:#### A) \(\cos\left(\frac{5\pi}{4}\right)\)#### B) \(\tan\left(-\frac{4\pi}{3}\right)\)#### C) \(\cot\left(-\frac{7\pi}{2}\right)\)#### D) \(\cos^{-1}\left(-\frac{\sqrt{3}}{2}\right)\)#### E) \(\sec\left(\sin^{-1}(1)\right)\)#### F) \(\csc\left(\frac{7\pi}{6}\right)\)#### G) \(\sin\left(-\frac{\pi}{6}\right)\)#### H) \(\tan^{-1}(0)\)#### I) \(\sec\left(\frac{14\pi}{3}\right)\)#### J) \(\cot\left(\csc^{-1}(2)\right)\)#### K) \(\sin^{-1}\left(-\frac{1}{\sqrt{2}}\right)\)#### L) \(\tan\left(\frac{13\pi}{4}\right)\)Each problem involves finding the trigonometric value or the inverse of a trigonometric function for specific angles or values, expressed in radians.

Solve the given problem.A) cos5π4=cosπ+π4=-cosπ4 as 5π4is in 3rd quadrant, cos is negative =-12 as value of cosπ4=12B) tan-4π3=tanπ-4π3 as tan has a period of π=tan-π3=-tanπ3 as -π3is in 4th quadrant, tan is negative =-3 as value of tanπ3=3 C) cot-7π2=1tan-7π2=1tan4π-7π2 as tan has a period of π=1tanπ2=cotπ2=0 as value of cotπ2=0