Find the equations of the normal line to the surface z = 3x¹y at the point (-2,-2, -1536) x=2688t - 2 768t - 2 Y = 2=-t+ 1536 X X 15/06/2023 14

Determine the coefficients a, b, c and d so that the curve y = ax* + bx³ + cx² + dx + e will pass through the points (0, 3), (–2,7) and have an inflection point at (1,4) with horizontal tangent.

Find the point P'symmetric of the point P(-5, 13) with respect to the line 2x - 3y - 3 = 0

Let Q = 4x2 + 6xy+ 4y? . The points on the curve Q = 7 which are closest to the origin are: %3D %3D OA(-눈-)and () (주·주) pue OB. (-V7, V7) and (v7, -V7) Oc. (0, ±1) OD. (tV7,0)