Find the equation of the tangent to the hyperbola x² – 3y² = 1 at the point S(2,-1). A) 2x + 3y – 1 = 0 B) 3x + 2y – 1 = 0 С) х — Зу — 2 %30 D) 2x – 3y = 0 E) х — Зу %3D 1
Find the equation of the tangent to the hyperbola x² – 3y² = 1 at the point S(2,-1). A) 2x + 3y – 1 = 0 B) 3x + 2y – 1 = 0 С) х — Зу — 2 %30 D) 2x – 3y = 0 E) х — Зу %3D 1
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![Find the equation of the tangent to the hyperbola x² – 3y? = 1 at the point S(2,-1).
A) 2x + 3y – 1 = 0
B) 3x + 2y – 1 = 0
С) х — Зу— 2 %3D 0
D) 2x – 3y = 0
E) х — Зу %3D 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2984eac2-4a5b-40fe-b6ae-67c017f1549b%2F6ee0f5a1-c1ff-4bd0-b3c0-21774243a6cd%2Fsbxavs8_processed.png&w=3840&q=75)
Transcribed Image Text:Find the equation of the tangent to the hyperbola x² – 3y? = 1 at the point S(2,-1).
A) 2x + 3y – 1 = 0
B) 3x + 2y – 1 = 0
С) х — Зу— 2 %3D 0
D) 2x – 3y = 0
E) х — Зу %3D 1
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