Find the equation of the tangent to the curve y = x+2x3 through point ( 8,12 ). a. 7x – 6y + 14 = 0 b. 8x + 5y + 21 = 0 с. 5х — бу-15%3D 0 d. Зx — 2y - 1 %3D0 e. None of the above

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the equation of the tangent to the curve y = x +2x3 through point ( 8,12 ).
a. 7x – 6y + 14 = 0
b. 8x + 5y + 21 = 0
с. 5х — бу— 15 %3D 0
d. 3x – 2y – 1 = 0
e. None of the above
Transcribed Image Text:Find the equation of the tangent to the curve y = x +2x3 through point ( 8,12 ). a. 7x – 6y + 14 = 0 b. 8x + 5y + 21 = 0 с. 5х — бу— 15 %3D 0 d. 3x – 2y – 1 = 0 e. None of the above
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