Find the equation of the tangent to the curve y = x+2x3 through point ( 8,12 ). a. 7x – 6y + 14 = 0 b. 8x + 5y + 21 = 0 с. 5х — бу-15%3D 0 d. Зx — 2y - 1 %3D0 e. None of the above

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Q: Find its equation in general form. а. — Зх — 8у — 35 %3D 0 b. Зх + 8у + 35 %3D 0 С. Зх — 8y — 35 3D…

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