Find the equation of the tangent line to the curve y = ○ y = 1/2 x 1/²/20 ○ y = x O O y = -2x - 5 y=1/x-1 - 3 at the point (4,1).

Q: Find the equation of the tangent line to y = 2"-5a -5x+1 = 4. at x = y = 12 In 2 - 1

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Q: Find the slope of the tangent line to the curve cos(За — Зу) — ае -37/2 2 at the point (37/2, 27).

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Q: Find equation of the tangent line to the curve y = v2x + 1 at the point (4,3).

A: Given:    y = √(2x+1)  Point (4,3)

Q: Compute the derivative of the given function. f(x) = 2x" + 1.9x8.7+ 8.7. Note: Use pi for 7 in your…

A: The first question only has been answer below by following the Bartleby guidelines.

Q: Find the slope of the tangent line to the curve 4x2 + 2xy - 2y³ = 160 at the point (4, - 4). -

A: We have to find slope of tangent line to the curve  at the point (4, -4) that is dy/dx at (4, -4)

Q: Find the slope of the tangent line to the curve 2x? + 4xy – ly = 40 at the point (2, - 4).

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Q: Find the equation of the tangent line to the curve y = (5 – 3x)² at z = –5.

A: To find the equation of the tangent line to the below curve at x = -5. y=5−3x2