Find the equation of the tangent line to the curve y = x³e7 at the point (1, e7). O y = 20e7x - 19e7 O y = 14e7x - 13e7 Oy=17e7x - 16e7 Oy=16e7 x - 15e7 O y = 15e7x - 14e7

Q: Find an equation of the tangent line to the curve y = 5 – 2x – 3x² at (1,0). y =

A: We will find the equation of the tangent line to the curve at the given point as following.

Q: Find an equation of the tangent line to the curve y = 9" at the point (1, 10).

A:

Q: Find an equation for the tangent line to the curve y = 4 at the point (3,16). X - 1 Oy - 16 = -3(x -…

A:

Q: 2. Find the equation of the tangent line to the curve. x=3t²+8t, y=2t²³-4t, whent=-2.

A: To find out the equation of the tangent line to the given curve when t=-2.

Q: Find the slope of the tangent line to the curve - 6y3 – 42?y? = 2 at the point (1, – 1)

A: We have to find slope of the tangent line to the curve -6y3-4x2y2=2 at the point 1,-1