Find the equation of the tangent line to a curve Y= \x at x= 4 4y - 8 -х%3D 0 4y -83D х-4 4y-x-4=0 4y + x -4 =0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the equation of the tangent line to a curve \( Y = \sqrt{x} \) at \( x = 4 \).

**Options:**

- \( \circ \) \( 4y - 8 - x = 0 \)

- \( \circ \) \( 4y - 8 = x - 4 \)

- \( \circ \) \( 4y - x - 4 = 0 \)

- \( \circ \) \( 4y + x - 4 = 0 \)
Transcribed Image Text:**Problem Statement:** Find the equation of the tangent line to a curve \( Y = \sqrt{x} \) at \( x = 4 \). **Options:** - \( \circ \) \( 4y - 8 - x = 0 \) - \( \circ \) \( 4y - 8 = x - 4 \) - \( \circ \) \( 4y - x - 4 = 0 \) - \( \circ \) \( 4y + x - 4 = 0 \)
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