Find the equation of the tangent line at (1, f(1)) when f(1) = 4 and f'(1) = 3. (Use symbolic notation and fractions where needed.)

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Finding the Equation of the Tangent Line**

The problem requires finding the equation of the tangent line at the point \((1, f(1))\) for the function \(f(x)\), given that \(f(1) = 4\) and \(f'(1) = 3\). The steps to solve this problem are detailed below:

---

**Problem Statement:**

Find the equation of the tangent line at \((1, f(1))\) when \(f(1) = 4\) and \(f'(1) = 3\).

*Use symbolic notation and fractions where needed.*

**Solution:**

To find the equation of the tangent line to the function \(f(x)\) at the point \((1, f(1))\):
1. We need to use the point-slope form of the equation of a line. 
2. The point-slope form is given by:
   \[
   y - y_1 = m(x - x_1)
   \]
   where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.

3. In this problem, \(x_1 = 1\), \(y_1 = f(1) = 4\), and the slope \(m = f'(1) = 3\).

Substituting these values into the point-slope form, we obtain:
\[
y - 4 = 3(x - 1)
\]

4. To express this in the slope-intercept form \(y = mx + b\) if needed, solve the equation for \(y\):
\[
y - 4 = 3x - 3 \implies y = 3x - 3 + 4 \implies y = 3x + 1
\]

**Equation:**

\[
y = 3x + 1
\]

---

This equation represents the tangent line to the function \(f(x)\) at the specified point.
Transcribed Image Text:**Finding the Equation of the Tangent Line** The problem requires finding the equation of the tangent line at the point \((1, f(1))\) for the function \(f(x)\), given that \(f(1) = 4\) and \(f'(1) = 3\). The steps to solve this problem are detailed below: --- **Problem Statement:** Find the equation of the tangent line at \((1, f(1))\) when \(f(1) = 4\) and \(f'(1) = 3\). *Use symbolic notation and fractions where needed.* **Solution:** To find the equation of the tangent line to the function \(f(x)\) at the point \((1, f(1))\): 1. We need to use the point-slope form of the equation of a line. 2. The point-slope form is given by: \[ y - y_1 = m(x - x_1) \] where \((x_1, y_1)\) is a point on the line and \(m\) is the slope. 3. In this problem, \(x_1 = 1\), \(y_1 = f(1) = 4\), and the slope \(m = f'(1) = 3\). Substituting these values into the point-slope form, we obtain: \[ y - 4 = 3(x - 1) \] 4. To express this in the slope-intercept form \(y = mx + b\) if needed, solve the equation for \(y\): \[ y - 4 = 3x - 3 \implies y = 3x - 3 + 4 \implies y = 3x + 1 \] **Equation:** \[ y = 3x + 1 \] --- This equation represents the tangent line to the function \(f(x)\) at the specified point.
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