Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Finding the Equation of the Tangent Line**
The problem requires finding the equation of the tangent line at the point \((1, f(1))\) for the function \(f(x)\), given that \(f(1) = 4\) and \(f'(1) = 3\). The steps to solve this problem are detailed below:
---
**Problem Statement:**
Find the equation of the tangent line at \((1, f(1))\) when \(f(1) = 4\) and \(f'(1) = 3\).
*Use symbolic notation and fractions where needed.*
**Solution:**
To find the equation of the tangent line to the function \(f(x)\) at the point \((1, f(1))\):
1. We need to use the point-slope form of the equation of a line.
2. The point-slope form is given by:
\[
y - y_1 = m(x - x_1)
\]
where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.
3. In this problem, \(x_1 = 1\), \(y_1 = f(1) = 4\), and the slope \(m = f'(1) = 3\).
Substituting these values into the point-slope form, we obtain:
\[
y - 4 = 3(x - 1)
\]
4. To express this in the slope-intercept form \(y = mx + b\) if needed, solve the equation for \(y\):
\[
y - 4 = 3x - 3 \implies y = 3x - 3 + 4 \implies y = 3x + 1
\]
**Equation:**
\[
y = 3x + 1
\]
---
This equation represents the tangent line to the function \(f(x)\) at the specified point.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f955ab0-b09c-40c5-989f-7e2adc5fa555%2Fca5ef62a-8d5c-4541-b6ff-883527fd9bd8%2F5ijd5m.png&w=3840&q=75)
Transcribed Image Text:**Finding the Equation of the Tangent Line**
The problem requires finding the equation of the tangent line at the point \((1, f(1))\) for the function \(f(x)\), given that \(f(1) = 4\) and \(f'(1) = 3\). The steps to solve this problem are detailed below:
---
**Problem Statement:**
Find the equation of the tangent line at \((1, f(1))\) when \(f(1) = 4\) and \(f'(1) = 3\).
*Use symbolic notation and fractions where needed.*
**Solution:**
To find the equation of the tangent line to the function \(f(x)\) at the point \((1, f(1))\):
1. We need to use the point-slope form of the equation of a line.
2. The point-slope form is given by:
\[
y - y_1 = m(x - x_1)
\]
where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.
3. In this problem, \(x_1 = 1\), \(y_1 = f(1) = 4\), and the slope \(m = f'(1) = 3\).
Substituting these values into the point-slope form, we obtain:
\[
y - 4 = 3(x - 1)
\]
4. To express this in the slope-intercept form \(y = mx + b\) if needed, solve the equation for \(y\):
\[
y - 4 = 3x - 3 \implies y = 3x - 3 + 4 \implies y = 3x + 1
\]
**Equation:**
\[
y = 3x + 1
\]
---
This equation represents the tangent line to the function \(f(x)\) at the specified point.
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